Interpretation:
The ratio of the partition functions at the same volume and temperature for a
Concept introduction:
Statistical
It is used to calculate the state functions like energy, pressure, wavelength etc. of the thermodynamic system. The expressions obtained for state functions using partition functions help to determine the statistical aspect of thermodynamic system.
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PHYSICAL CHEMISTRY-STUDENT SOLN.MAN.
- A certain atom has a triply degenerate ground level, a non-degenerate electronically excited level at 850 cm–1, and a fivefold degenerate level at 1100 cm−1. Calculate the partition function of these electronic states at 2000 K. What is the relative population of each level at 2000 K?arrow_forwardConsider a system of distinguishable particles having only two non-degenerate levels separated by an energy that is equal to the value of kT at 10 K. Calculate (a) the ratio of populations in two states at (1) 1.0 K, (2) 10 K, (3) 100 K, (b) the molecular partition function at 10 K, (c) the molar energy at 10 K, (d) the molar heat capacity at 10 K, € the molar entropy at 10 K.arrow_forwardA system comprising of one mole of distinguishable and non-interacting molecules has a two-fold degenerate ground energy level, a two-fold degenerate excited energy level at 1237 cm1 and a nondegenerate excited energy level at 2010 cm-1 at 300 K and 1 atm. Calculate (b) the partition function, q. (1) the number of molecules in each energy level. the change in the ratio of the molecules in the first excited energy level with respect to the ground energy level when the temperature increases by 10-fold. (ii) (iv) the total energy, E. (v) the partition function when T = 0.arrow_forward
- system A with 100,000 molecules is at equilibrium at 400k with a boltzmann partition function of q=1.156518. Assume that the energy levels for system A are evenly distributed at delta U = 2Kb x T . a) calculate the probability and population distribution for the system? ( use 5 energy levels including ground state) b) calculate the entropy for the system?arrow_forward4) Consider a chemical reaction R⇒ P at 300 K. R has two states separated by 2.0x10-22 J. P has a doubly degenerate level that is 1.0x10-22 J above the ground state of P. a) Which one has a larger molecular partition function? b) Find the equilibrium constant for the reaction.arrow_forwardE e q kT where k is The probability of a molecule having energy E is P (E) Boltzmann's constant (1.38 * 10¯²³J/K) and q is the partition function. A system has three possible energy levels: 0 cm³¹, 100 cm³¹, and 250 cm³¹. The temperature is 300 K. a) Convert each energy level to J/molecule. (Double check your units!) b) Find q, the partition function (sum up the unnormalized probabilities). The degeneracy of all levels = 1 c) Calculate the average energy (expectation value) of a molecule in units of cm³¹. Make sure to use normalized probabilities. d) Plot P vs E. Make sure to use normalized probabilities.arrow_forward
- Give the equation for the Helmholtz energy, A. (Use the following as necessary: S, T, and U.) A = U-TS - TS Give the equation for entropy that contains the canonical partition function, Q. (Use the following as necessary: E, kB, Q, and T.) E E S = k ln(Q) + B kB ln (Q) + Step 2 of 7 We only need to consider the translational translational partition function for an ideal monatomic gas, so E = U - Uo. Combine this equation with the equations for S and A from Step 1. (Use the following as necessary: KB, Q, T, U, and Up.) A = |— Tkôln(Q) + U U₁ - KBT ln(Q) Step 3 of 7 Substitute the equation from Step 2 into the given equation for P and complete the partial derivative. (Use the following as necessary: kB, Q, T, U, and Up.) -(SA), P = - a In(Q)). KBT = KBT Step 4 of 7 For an ideal monatomic gas, the following is true. (Use the following as necessary: T, U, and V.) (U) = UT - 0 Step 5 of 7 Give the equation for the canonical partition function Q. Remember that only the translational…arrow_forward12.10 Calculate the molar entropy of nitrogen gas at 298 K. Write the overall partition function as the product of the trans- lational and rotational partition functions; the first excited vibrational state is sufficiently high in energy that the contri- bution from vibration of the molecule may be ignored at this temperature. The rotational constant of N₂ is 2.00 cm™¹.arrow_forwardNitric oxide, NO, has two low-lying electronic states. The lowest electronic state has a degeneracy of 2. The second state lies the equivalent of 121 cm-1 higher and has a degeneracy of 4. The next electronic state is much higher inenergy. Calculate the electronic partition function at 298 K.arrow_forward
- Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,