The equilibrium partial pressure of NOCl (g) has to be calculated. Concept Introduction: Equilibrium constant ( K p ) : In gas phase reactions, partial pressure is used to write equilibrium equation than molar concentration. Equilibrium constant ( K p ) is defined as ratio of partial pressure of products to partial pressure of reactants. Each partial pressure term is raised to a power, which is same as the coefficients in the chemical reaction Consider the reaction where A reacts to give B. aA ⇌ bB Rate of forward reaction = Rate of reverse reaction k f P A a =k r P B a On rearranging, P B b P A a = k f k r =K p Where, k f is the rate constant of the forward reaction. k r is the rate constant of the reverse reaction. K p is the equilibrium constant.
The equilibrium partial pressure of NOCl (g) has to be calculated. Concept Introduction: Equilibrium constant ( K p ) : In gas phase reactions, partial pressure is used to write equilibrium equation than molar concentration. Equilibrium constant ( K p ) is defined as ratio of partial pressure of products to partial pressure of reactants. Each partial pressure term is raised to a power, which is same as the coefficients in the chemical reaction Consider the reaction where A reacts to give B. aA ⇌ bB Rate of forward reaction = Rate of reverse reaction k f P A a =k r P B a On rearranging, P B b P A a = k f k r =K p Where, k f is the rate constant of the forward reaction. k r is the rate constant of the reverse reaction. K p is the equilibrium constant.
Definition Definition Study of the speed of chemical reactions and other factors that affect the rate of reaction. It also extends toward the mechanism involved in the reaction.
Chapter 17, Problem 17.46P
Interpretation Introduction
Interpretation:
The equilibrium partial pressure of NOCl(g) has to be calculated.
Concept Introduction:
Equilibrium constant(Kp):
In gas phase reactions, partial pressure is used to write equilibrium equation than molar concentration. Equilibrium constant (Kp) is defined as ratio of partial pressure of products to partial pressure of reactants. Each partial pressure term is raised to a power, which is same as the coefficients in the chemical reaction
Consider the reaction where A reacts to give B.
aA⇌bB
Rate of forward reaction = Rate of reverse reactionkfPAa=krPBa
First image: Why can't the molecule C be formed in those conditions
Second image: Synthesis for lactone C
its not an exam
First image: I have to show the mecanism for the reaction on the left, where the alcohol A is added fast in one portion
Second image: I have to show the mecanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary
First image: I have to explain why the molecule C is never formed in those conditions.
Second image: I have to propose a synthesis for the lactone A
Chapter 17 Solutions
Chemistry: The Molecular Nature of Matter and Change
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