The conversion of acetylene to ethylene is given as C 2 H 2(g) + H 2(g) ⇌ C 2 H 4(g) The calculated K c at 2000 .K is 2 .9×10 8 . But the process is run at lower temperatures with the aid of a catalyst to prevent decomposition. By using ΔH ° values, K c has to be calculated at 300 .K . Concept Introduction: Equilibrium constant: The relationship between the concentration of products and concentration of reactants in a chemical reaction at equilibrium is said to be equilibrium constant. It is denoted by K . For a reaction, xX + yY ⇌ zZ The expression of K can be given as K c = [Z] z [X] x [Y] y where, [X] = equilibrium concentration of X [Y] = equilibrium concentration of Y [Z] = equilibrium concentration of Z
The conversion of acetylene to ethylene is given as C 2 H 2(g) + H 2(g) ⇌ C 2 H 4(g) The calculated K c at 2000 .K is 2 .9×10 8 . But the process is run at lower temperatures with the aid of a catalyst to prevent decomposition. By using ΔH ° values, K c has to be calculated at 300 .K . Concept Introduction: Equilibrium constant: The relationship between the concentration of products and concentration of reactants in a chemical reaction at equilibrium is said to be equilibrium constant. It is denoted by K . For a reaction, xX + yY ⇌ zZ The expression of K can be given as K c = [Z] z [X] x [Y] y where, [X] = equilibrium concentration of X [Y] = equilibrium concentration of Y [Z] = equilibrium concentration of Z
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 17, Problem 17.91P
Interpretation Introduction
Interpretation:
The conversion of acetylene to ethylene is given as
C2H2(g)+ H2(g)⇌C2H4(g)
The calculated Kc at 2000.K is 2.9×108. But the process is run at lower temperatures with the aid of a catalyst to prevent decomposition. By using ΔH° values, Kc has to be calculated at 300.K.
Concept Introduction:
Equilibrium constant:
The relationship between the concentration of products and concentration of reactants in a chemical reaction at equilibrium is said to be equilibrium constant. It is denoted by K.
For a reaction,
xX + yY ⇌ zZ
The expression of K can be given as
Kc = [Z]z[X]x[Y]ywhere,[X] = equilibrium concentration of X[Y] = equilibrium concentration of Y[Z] = equilibrium concentration of Z
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
Chapter 17 Solutions
Chemistry: The Molecular Nature of Matter and Change
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