K c for the given reaction CO (g) + Cl 2(g) ⇌ COCl 2(g) has to be calculated. Concept Introduction: Relation between K p and K c : The relation between and K p and K c is given by the following equation. K p = K c (RT) Δ ngas Where, K p is the equilibrium constant in terms of partial pressure K c is the equilibrium constant in terms of concentration Δ n ( gas ) = moles of gaseous product - moles of gaseous reactant Only moles of gaseous products and reactants is used to calculate Δ ngas
K c for the given reaction CO (g) + Cl 2(g) ⇌ COCl 2(g) has to be calculated. Concept Introduction: Relation between K p and K c : The relation between and K p and K c is given by the following equation. K p = K c (RT) Δ ngas Where, K p is the equilibrium constant in terms of partial pressure K c is the equilibrium constant in terms of concentration Δ n ( gas ) = moles of gaseous product - moles of gaseous reactant Only moles of gaseous products and reactants is used to calculate Δ ngas
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!
Q1: Answer the questions for the reaction below:
..!! Br
OH
a) Predict the product(s) of the reaction.
b) Is the substrate optically active? Are the product(s) optically active as a mix?
c) Draw the curved arrow mechanism for the reaction.
d) What happens to the SN1 reaction rate in each of these instances:
1. Change the substrate to
Br
"CI
2. Change the substrate to
3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF
4. Increase the substrate concentration by 3-fold.
Chapter 17 Solutions
Chemistry: The Molecular Nature of Matter and Change
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