Interpretation:
The observation that the N,N,N-trimethylammonium group –N(CH3)3, though a meta directing deactivator does not exhibit electron withdrawing resonance effect is to be explained.
Concept introduction:
In planar molecules the overlapping of p orbitals on adjacent carbon atoms takes place leading to the formation of different resonance forms. Resonance is not possible if the molecule is not co-planar.
If the group already present on the benzene ring is electron withdrawing by resonance and/or inductive effect it will deactivate the ring towards electrophiles.
The stability of a resonance hybrid depends on the number of stable individual resonance forms that contribute to the hybrid. More the number, the more stable is the hybrid.
To explain:
The observation that the N,N,N-trimethylammonium group –N(CH3)3, though a meta directing deactivator does not exhibit electron withdrawing resonance effect.

Trending nowThis is a popular solution!

Chapter 16 Solutions
ORGANIC CHEMISTRY W/OWL
- Polymers may be composed of thousands of monomers. Draw three repeat units (trimer) of the polymer formed in this reaction. Assume there are hydrogen atoms there are hydrogen atoms on the two ends of the trimer. Ignore inorganic byproducts please.arrow_forwardi need help with the folarrow_forwardPLEASE HELP NOW! URGENT!arrow_forward
- a. Determine whether each of the Followery Molecules is in the R- On the y- Configuration 1-01"/ 1-6-4 Br 4 I el Br b. Draw The Fisher projection For all the Meso compounds that can exist FOR The Following molenlearrow_forward1- Refer to the monosaccharides below to answer each of the following question(s): CH₂OH CHO CH₂OH CH₂OH 0 H- OH 0 0 HO- H H- -OH HO H HO H H OH HO- H CH₂OH H. OH HO H HO- H CH₂OH CH₂OH CH3 a. Sorbose b. Rhamnose c. Erythrulose d. Xylulose Classify each sugar by type; for example, glucose is an aldohexose. a. Xylulose is .. b. Erythrulose is . c. Sorbose is .. d. Rhamnose is .. 2- Consider the reaction below to answer the following question(s). CHO H OH CH₂OH CH₂OH HO- H HO HO + H. -OH HO OH HO. H OH OH H -OH H OH CH₂OH Q Z a. Refer to Exhibit 25-11. Place a triangle around the anomeric carbon in compound Q. Compound Z is: b. 1. the D-anomer. 2. the a-anomer. 3. the ẞ-anomer. 4. the L-anomer. c. Which anomer is the LEAST stable? d. Q and Z are cyclic examples of: a. acetals b. hemiacetals c. alditols d. hemialditolsarrow_forwardi need help identifying the four carbon oxygen bonds in the following:arrow_forward
- Imagine each of the molecules shown below was found in an aqueous solution. Can you tell whether the solution is acidic, basic, or neutral? molecule HO H3N + The solution is... X O acidic OH O basic H3N-CH-C-O O neutral ○ (unknown) O acidic ○ basic CH2 CH 3-S-CH2 O neutral ○ (unknown) H3N O OH O acidic O basic Oneutral O (unknown) 0 H3N-CH-C-O CH3 CH CH3 O acidic O basic O neutral ○ (unknown) ? olo Ar BHarrow_forwardno Ai walkthroughs need other product (product in picture is wrong dont submit the same thing)arrow_forwardHow to solve this!arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

