The hatchback of a car is positioned as shown to help determine the appropriate size for a damping
(a)
(b)
Fig. P16.134
(a)
The initial angular acceleration of the door.
Answer to Problem 16.134P
The initial angular acceleration of the door is
Explanation of Solution
Given information:
The weight of the door is
The mass moment of inertia of the center of gravity is
Calculation:
Consider the acceleration due to gravity as
Calculate the mass
Substitute
Sketch the Free Body Diagram of the door as shown in Figure 1.
Refer to Figure 1.
Calculate the distance
Calculate the distance
Calculate the position vectors as shown below.
The position of F with respect to H.
The position of E with respect to F.
Substitute
The position of E with respect to D.
The position of G with respect to E.
Apply the Equations of Equilibrium as shown below.
Apply the Equilibrium of forces along x direction as shown below.
Substitute
Apply the Equilibrium of forces along y direction as shown below.
Substitute
Substitute
Apply the Equilibrium of moment about G as shown below.
Calculate the acceleration at F
Substitute
Calculate the acceleration at E
Substitute
Calculate the acceleration at E
Substitute
Equating Equations (4) and (5) as shown below.
Resolving i and j components as shown below.
For i component.
For j component.
Calculate the relative acceleration
Substitute
Resolving i and j components as shown below.
For i component.
For j component.
Calculate the force at F
Substitute
Substitute
Calculate the force at E
Substitute
Substitute
Calculate the angular acceleration
Substitute
Therefore, the initial angular acceleration of the door is
(b)
The force on link FH.
Answer to Problem 16.134P
The force on link FH is
Explanation of Solution
Given information:
The weight of the door is
The mass moment of inertia of the center of gravity is
Calculation:
Refer to part (a).
The initial angular acceleration of the door is
Calculate the force at F
Substitute
Therefore, the force on link FH is
Want to see more full solutions like this?
Chapter 16 Solutions
Vector Mechanics for Engineers: Statics and Dynamics
Additional Engineering Textbook Solutions
Introduction To Programming Using Visual Basic (11th Edition)
SURVEY OF OPERATING SYSTEMS
Problem Solving with C++ (10th Edition)
Fluid Mechanics: Fundamentals and Applications
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Thinking Like an Engineer: An Active Learning Approach (4th Edition)
- The hose supplying the cylinder operating the bucket of a large excavator has fluid at 1000 psi flowing at 5 gpm. What is theavailable power in the line?arrow_forwardQ For the following plan of building foundation, Determine immediate settlement at points (A) and (B) knowing that: E,-25MPa, u=0.3, Depth of foundation (D) =1m, Depth of layer below base level of foundation (H)=10m. 3m 2m 100kPa A 2m 150kPa 5m 200kPa Barrow_forwardGiven the following data for crack rocker mechanism. If θ2 = 4π/3 and ω2 = 1 rad/s, Determine all possible values of ω4 and ω3 analytically. The lengths of links are a = 2, b = 8, c = 7 and d = 9 in cm.arrow_forward
- Q6] (20 Marks) Select the most suitable choice for the following statements: modo digi -1A 10 af5 1 -The copper-based alloy which is responded to age hardening is a) copper-nickel b) aluminum bronze c) copper - beryllium d) brass besincaluy 2- Highly elastic polymers may experience elongations to greater than.... b) 500% bromsia-P c) 1000%. d) 1200% 15m or -2 a)100% 3- The cooling rate of quenching the steel in saltwater will be ......the cooling rate of quenching ir c) faster than sold) none of them a) slower than 4- Adding of a) Cr b) the same as ...... Will lead to stabilize the b) Mo 10 austenite in steel. c) Nimble avolls 1d) Sized loloin nl 5- The adjacent linear chains of crosslinked polymers are joined one to another at various positic DIR... by.........bonds c) covalent noisqo gd) ionic lg 120M 6- For the ceramic with coordination number 6 the cation to anion radius ratio will be a) Van der Waals a) 0.155-0.225 a) linear b) hydrogen (b) 0.225-0.414 c) 0.414 0.732 ..polymers.…arrow_forwardExamine Notes: Attempt Six Questions Only. rever necessa , Q1] (20 Marks) Answer with true (T) or false (F), corrects the wrong phrases, and gives sho reasons for correct and corrected statements: 1- High chromium irons are basically grey cast irons alloyed with 12 to 30 % Cr. yous board-19qgo orT-1 2- The drawbacks of Al- Li alloys are their high young modulus and high density.&M 0) (0 3- Vulcanized rubbers are classified under thermoplastic polymers. 4- Diamond is a stable carbon polymorph at room temperature and atmospheric pressure. ( 5- The metallic ions of ceramic are called anions, and they are positively charged. yldgiH-S 69001(6arrow_forwardH.W 5.4 Calculate the load that will make point A move to the left by 6mm, E-228GPa. The diameters of the rods are as shown in fig. below. 2P- PA 50mm B 200mm 2P 0.9m 1.3marrow_forward
- d₁ = = Two solid cylindrical road AB and BC are welded together at B and loaded as shown. Knowing that 30mm (for AB) and d₂ 50mm (for BC), find the average normal stress in each road and the total deformation of road AB and BC. E=220GPa H.W 5.3 60kN A For the previous example calculate the value of force P so that the point A will not move, and what is the total length of road AB at that force? P◄ A 125kN 125kN 0.9m 125kN 125kN 0.9m B B 1.3m 1.3marrow_forwardClass: B Calculate the load that will make point A move to the left by 6mm, E-228GPa The cross sections of the rods are as shown in fig. below. 183 P- Solution 1.418mm 200mm 80mm 3P- 18.3 A 080mm B 200mm 3P- 0.9m إعدادات العرض 1.3m 4.061mmarrow_forwardH.W6 Determine the largest weight W that can be supported by two wires shown in Fig. P109. The stress in either wire is not to exceed 30 ksi. The cross- sectional areas of wires AB and AC are 0.4 in2 and 0.5 in2, respectively. 50° 30° Warrow_forward
- Find equation of motion and natural frequency for the system shown in fig. by energy method. H.W2// For the system Fig below find 1-F.B.D 2-Eq.of motion 8wn 4-0 (5) m. Jo marrow_forward2. Read the following Vernier caliper measurements. (The scales have been enlarged for easier reading.) The Vernier caliper is calibrated in metric units. (a) 0 1 2 3 4 5 سلسلسله (b) 1 2 3 4 5 6 سلسل (c) 1 23456 (d) 1 2 3 4 5 6 سلسلسarrow_forwardExplain why on the interval 0<x<1000 mm and 1000<x<2000mm, Mt is equal to positive 160 Nm, but at x= 0mm and x=1000mm Mt is equal to -160 Nm (negative value!). What is the reason for the sign change of Mt?arrow_forward
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY