
To find : the domain of the function so that the function is one-to-one and has an inverse function. And find the inverse function.

Answer to Problem 88E
The domain of function f is x≥0 for having one-to-one function and inverse function is f−1(x)=√2x−2.
Explanation of Solution
Given information :
The function f(x)=12x2+1.
Calculation : the domain of function is all real numbers. To having the function one-to-one and inverse, for every value of x , there should be unique value of y.
So the domain of function should be x≥0.
To find the inverse function substitute f(x)=y in the function and simplify it,
f(x)=12x2+1y=12x2+1 [substitute f(x)=y]12x2=y−1 [subtract 1 both side]x2=2y−2 [multiply by 2]x=√2y−2 [sqaure root]f−1(x)=√2x−2 [simplify]
Thus, the inverse function is f−1(x)=√2x−2.
The domain of the function f is all real values because function is defined for all real values.
The minimum value of function 1 occurs at x=0.
Thus, The range of the function f is [1,∞).
The domain of function f−1 is the range of the function f.
Thus, the domain of the function f−1 is [1,∞).
For range of the function f−1 , the minimum value 0 is occur at x=1 ,
Thus, the range of the function f−1 is [0,∞).
Chapter 1 Solutions
Precalculus with Limits: A Graphing Approach
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