Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 16, Problem 64A
Interpretation Introduction

Interpretation:

To explain how the instantaneous rate of the reaction H2(g)+2NO(g)H2O(g)+N2O(g) changes as the initial concentration of H2 changed.

Concept introduction:

The given reaction is as follows:

H2(g)+2NO(g)H2O(g)+N2O(g)

Rate law of the reaction is-

Rate=k[NO]2[H2]

The rate law was calculated from experimental data suggesting that the rate depends on the reactant concentration as follows: If [NO] doubles, the rate quadruples; if H2 doubles, the rate doubles.

Expert Solution & Answer
Check Mark

Answer to Problem 64A

Instantaneous rate of the reaction increases by 1.8 times with change in initial concentration of H2. And it is the part of the rate law.

Explanation of Solution

The given reaction is as follows:

H2(g)+2NO(g)H2O(g)+N2O(g)

Concentration of H2 measured at three successive points during the experiment is given in table.

[H2](mol/L) Instantaneous rate

(mol/L.s)

0.18 6.00×103
0.32 1.07×102
0.58 1.93×102

From the table it is clear that concentration of H2 increased by 1.8 times from first line to the second and also rate is increased by about 1.8 times.

Again, see the changes of concentration of H2 from lines 2 to 3. Concentration of H2 increased by 1.8 times and also rate is increased by about 1.8 times. Hence, H2 is a part of the rate law and it is first order reaction.

Conclusion

Rate of the reaction increased with increase in the reactant concentration. The reactant concentration H2 is increased in each step by 1.8. Therefore, it is a part of the rate law.

Chapter 16 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 16.1 - Prob. 11SSCCh. 16.1 - Prob. 12SSCCh. 16.2 - Prob. 13SSCCh. 16.2 - Prob. 14SSCCh. 16.2 - Prob. 15SSCCh. 16.2 - Prob. 16SSCCh. 16.2 - Prob. 17SSCCh. 16.2 - Prob. 18SSCCh. 16.3 - Prob. 19PPCh. 16.3 - Prob. 20PPCh. 16.3 - Prob. 21PPCh. 16.3 - Prob. 22PPCh. 16.3 - Prob. 23SSCCh. 16.3 - Prob. 24SSCCh. 16.3 - Prob. 25SSCCh. 16.3 - Prob. 26SSCCh. 16.3 - Prob. 27SSCCh. 16.3 - Prob. 28SSCCh. 16.3 - Prob. 29SSCCh. 16.3 - Prob. 30SSCCh. 16.4 - Prob. 31PPCh. 16.4 - Prob. 32PPCh. 16.4 - Prob. 33PPCh. 16.4 - Prob. 34SSCCh. 16.4 - Prob. 35SSCCh. 16.4 - Prob. 36SSCCh. 16.4 - Prob. 37SSCCh. 16.4 - Prob. 38SSCCh. 16.4 - Prob. 39SSCCh. 16 - Prob. 40ACh. 16 - Explain what is meant by the average rate of a...Ch. 16 - How would you express the rate of the chemical...Ch. 16 - What is the role of the activated complex in a...Ch. 16 - Suppose two molecules that can react collide....Ch. 16 - Prob. 45ACh. 16 - If AB is exothermic, how does the activation...Ch. 16 - In the gas-phase reaction, I2+Cl22ICl,[I2]...Ch. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - In general, what is the relationship between...Ch. 16 - Apply collision theory to explain why increasing...Ch. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Apply collision theory to explain why powdered...Ch. 16 - Hydrogen peroxide decomposes to water and oxygen...Ch. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 64ACh. 16 - Prob. 65ACh. 16 - Prob. 66ACh. 16 - Prob. 67ACh. 16 - Prob. 68ACh. 16 - Prob. 69ACh. 16 - Prob. 70ACh. 16 - Prob. 71ACh. 16 - Prob. 72ACh. 16 - Prob. 73ACh. 16 - Prob. 74ACh. 16 - Prob. 75ACh. 16 - Prob. 76ACh. 16 - Prob. 77ACh. 16 - Prob. 78ACh. 16 - Prob. 79ACh. 16 - Prob. 80ACh. 16 - Prob. 81ACh. 16 - Prob. 82ACh. 16 - Prob. 83ACh. 16 - Differentiate between the shaded areas in Figure...Ch. 16 - Apply the method of initial rates to determine the...Ch. 16 - Prob. 86ACh. 16 - Prob. 87ACh. 16 - Prob. 88ACh. 16 - Create a table of concentrations, starting with...Ch. 16 - Prob. 90ACh. 16 - Prob. 91ACh. 16 - Prob. 92ACh. 16 - Prob. 93ACh. 16 - Prob. 94ACh. 16 - Prob. 95ACh. 16 - Prob. 96ACh. 16 - Prob. 97ACh. 16 - Prob. 99ACh. 16 - Prob. 100ACh. 16 - Prob. 101ACh. 16 - Prob. 102ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Use the diagram below to answer Questions 8 and 9....Ch. 16 - Prob. 10STPCh. 16 - Prob. 11STPCh. 16 - Prob. 12STPCh. 16 - Prob. 13STPCh. 16 - Prob. 14STPCh. 16 - Prob. 15STPCh. 16 - Prob. 16STPCh. 16 - Prob. 17STPCh. 16 - Prob. 18STPCh. 16 - Prob. 19STP
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