Chapter 16, Problem 49A

Interpretation Introduction

Interpretation:

The rate expressed in moles per liter per minutes for a chemical reaction at the rate of $2.25\times {10}^{-2}$ moles per liter per second at 322 K needs to be determined

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side.

The average rate of a reaction can be given by the formula,

Average reaction rate $\text{=}-\frac{\text{Δ}\left[\text{reactant}\right]}{\text{Δt}}$

Here, $\text{Δ}\left[\text{reactant}\right]$ = change in the concentration of the reactant

Answer to Problem 49A

The reaction rate for the reaction at the rate of $2.25\times {10}^{-2}$ moles per liter per second at 322 Kis $1.35\frac{\text{mol}}{\text{L}\text{.min}}$

Explanation of Solution

Given, the rate of chemical reaction is $2.25\times {10}^{-2}$ moles per liter per second at temperature 322 K. The reaction rate has to be multiplied by a factor $\frac{60\text{s}}{1\min }$

So, reaction rate will be,

$\begin{array}{l}=\text{2}{\text{.25×10}}^{\text{-2}}\frac{\text{mol}}{\text{L}\text{.s}}\\ =\left(\text{2}{\text{.25×10}}^{\text{-2}}\frac{\text{mol}}{\text{L}\text{.s}}\right)\left(\frac{\text{60}\text{s}}{\text{1min}}\right)\\ =\left(\text{2}{\text{.25×10}}^{\text{-2}}\times 60\right)\left(\frac{\text{mol}}{\text{1min}}\right)\\ =1.35\frac{\text{mol}}{\text{L}\text{.min}}\end{array}$

Therefore, the reaction rate is $1.35\frac{\text{mol}}{\text{L}\text{.min}}$

Conclusion

The reaction rate for the given reaction is $1.35\frac{\text{mol}}{\text{L}\text{.min}}$