Chapter 16, Problem 58A

Interpretation Introduction

Interpretation:

The amount of oxygen gas produced by an identical solution in 100 s at 308K needs to be determined.

Concept introduction:

Rate of a chemical reaction is the change in concentration of a reactant or product per unit of time, expressed as mol/(L.s). Different factors like the nature of reactants, concentration, surface area and temperature affect the rate of the reaction. The rate of the reaction increases with increasing temperature.

Answer to Problem 58A

The resultant oxygen gas produced at 308 K is $24\text{mL}$.

Explanation of Solution

Consider the graph of the relative reaction rate and temperature of a reaction.

The data marks are given as (Temperature, rate).

The given data points from the graph is as follows: (290K, 2), (310K, 8), (320K, 16) and (330K, 32). The temperature is raised by 10K. Therefore, it is clear that the reaction rate should double from 2 to 4.

At temperature 298K, $3\%$ of hydrogen peroxide decomposes to yield 12 mL of oxygen gas in 100 s. When the same experiment run by adding temperature by 10K that means at 308 K, according to the graph the rate should be doubled.

Since at temperature 298K 12 mL oxygen gas is produced. Therefore,

At 308 K, $2\times 12=24\text{mL}$ oxygen gas is produced.

Conclusion

The resultant oxygen gas produced at At 308 K is $24\text{mL}$.