
Interpretation:
To identify the labels in the given figure.
Concept introduction:
An activated complex is formed as a result of collision between two particles with a sufficient amount of energy required for the collision. When the colliding particles break their bonds to form new bonds with the atoms of the particles it has undergo collision, a temporary transition state is generated which is an activated complex.

Answer to Problem 72A
In figure 16.23, label 1 represents the reactants, label 2 represents the activated complex, label 3 represents intermediate step, label 4 represents activated complex., label 5 represents products and label 6 also represents the activated complex.
Explanation of Solution
From the figure,
Each step signifies a series of elementary reactions. The reaction begins with the reactants and proceeds through an intermediate to generate products.
Label 1 represents the reactants as it is located at the beginning of the reaction.
Label 2 represents an activated complex because it is located just after label 1.
Label 3 represents the intermediate step because the curve in this location is lower in energy than that of the activated complex.
The intermediate which is produced from the first elementary step used as reactants in the second elementary step. An activated complex is generated when the intermediates react.
This particular elementary step includes an activated complex with a higher energy than in the previous elementary step. Label 4 represents the activated complex.
The products are formed after the activated complex briefly occurs in the second elementary step. Label 5 represents the products. The products located in label 5 is lower in energy than that of the activated complex.
The intermediate that is produced from the second elementary step is used as a reactant in the third elementary step. These intermediates react to generate an activated complex. Label 6 represents the activated complex.
Label 1 represents reactants, label 2 represents activated complex, label 3 represents the intermediate step, label 4 represents the activated complex, label 5 represents the products and label 6 represents the activated complex
Chapter 16 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
Additional Science Textbook Solutions
Anatomy & Physiology (6th Edition)
Chemistry: Structure and Properties (2nd Edition)
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology (11th Edition)
Human Anatomy & Physiology (2nd Edition)
Campbell Essential Biology (7th Edition)
- 7. The three sets of replicate results below were accumulated for the analysis of the same sample. Pool these data to obtain the most efficient estimate of the mean analyte content and the standard deviation. Lead content/ppm: Set 1 Set 2 Set 3 1. 9.76 9.87 9.85 2. 9.42 9.64 9.91 3. 9.53 9.71 9.42 9.81 9.49arrow_forwardDraw the Zaitsev product famed when 2,3-dimethylpentan-3-of undergoes an El dehydration. CH₂ E1 OH H₁PO₁ Select Draw Templates More QQQ +H₂Oarrow_forwardComplete the clean-pushing mechanism for the given ether synthesia from propanol in concentrated sulfurica140°C by adding any mining aloms, bands, charges, nonbonding electron pairs, and curved arrows. Draw hydrogen bonded to cayan, when applicable. ore 11,0 HPC Step 1: Draw curved arrows Step 2: Complete the intend carved Q2Q 56 QQQ Step 3: Complete the intermediate and add curved Step 4: Modify the structures to draw the QQQ QQQarrow_forward
- 6. In an experiment the following replicate set of volume measurements (cm3) was recorded: (25.35, 25.80, 25.28, 25.50, 25.45, 25.43) A. Calculate the mean of the raw data. B. Using the rejection quotient (Q-test) reject any questionable results. C. Recalculate the mean and compare it with the value obtained in 2(a).arrow_forwardA student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. • If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T G OH де OH This transformation can't be done in one step.arrow_forwardMacmillan Leaming Draw the major organic product of the reaction. 1. CH3CH2MgBr 2. H+ - G Select Draw Templates More H о QQarrow_forward
- Draw the condensed structure of 3-hydroxy-2-butanone. Click anywhere to draw the first atom of your structure.arrow_forwardGive the expected major product of reaction of 2,2-dimethylcyclopropane with each of the following reagents. 2. Reaction with dilute H₂SO, in methanol. Select Draw Templates More CHC Erase QQQ c. Reaction with dilute aqueous HBr. Select Drew Templates More Era c QQQ b. Reaction with NaOCH, in methanol. Select Draw Templates More d. Reaction with concentrated HBr. Select Draw Templates More En a QQQ e. Reaction with CH, Mg1, then H*, H₂O 1. Reaction with CH,Li, then H', H₂Oarrow_forwardWrite the systematic name of each organic molecule: structure O OH OH name X ☐arrow_forward
- Macmillan Learning One of the molecules shown can be made using the Williamson ether synthesis. Identify the ether and draw the starting materials. А со C Strategy: Review the reagents, mechanism and steps of the Williamson ether synthesis. Determine which of the molecules can be made using the steps. Then analyze the two possible disconnection strategies and deduce the starting materials. Identify the superior route. Step 6: Put it all together. Complete the two-step synthesis by selecting the reagents and starting materials. C 1. 2. Answer Bank NaH NaOH NaOCH, снен, сен, он Сиси, Сне (СН), СОН (Сн, Свarrow_forwardWrite the systematic name of each organic molecule: structure CH3 O CH3-CH-CH-C-CH3 OH HV. CH3-C-CH-CH2-CH3 OH CH3 O HO—CH, CH–CH—C CH3 OH 오-오 name X G ☐arrow_forwardHI Organic Functional Groups Predicting the reactants or products of esterification What is the missing reactant in this organic reaction? HO OH H +回 + H₂O 60013 Naomi V Specifically, in the drawing area below draw the skeletal ("line") structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. No answer Click and drag to start drawing a structure. Explanation Check 1 2 #3 $ 4 2025 % ala5 'a :☐ G & 67 8 Ar K enter Accessible 9 Q W E R TY U 1 tab , S H J Karrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





