Concept explainers
(a)
Interpretation:
The base having strong conjugate acid is to be chosen.
Concept introduction:
According to Arrhenius, acid is a substance which produces hydrogen ion and Base is a substance which produces hydroxyl ions in an aqueous solution.
According to Bronsted-Lowry, acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.
(a)
Answer to Problem 58A
Base
Explanation of Solution
The equation can be written as:
Equilibrium lies more towards reactant side. Therefore,
(b)
Interpretation:
The base having strong conjugate acid is to be chosen.
Concept introduction:
According to Arrhenius, acid is a substance which produces hydrogen ion and Base is a substance which produces hydroxyl ions in an aqueous solution.
According to Bronsted-Lowry, acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.
(b)
Answer to Problem 58A
Base
Explanation of Solution
The equation can be written as:
Equilibrium lies more towards right side. Therefore,
(c)
Interpretation:
The base having strong conjugate acid is to be chosen.
Concept introduction:
According to Arrhenius, acid is a substance which produces hydrogen ion and Base is a substance which produces hydroxyl ions in an aqueous solution.
According to Bronsted-Lowry, acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.
(c)
Answer to Problem 58A
Base
Explanation of Solution
The equation can be written as:
Equilibrium lies more towards reactant side. Therefore,
(d)
Interpretation:
The base having strong conjugate acid is to be chosen.
Concept introduction:
According to Arrhenius, acid is a substance which produces hydrogen ion and Base is a substance which produces hydroxyl ions in an aqueous solution.
According to Bronsted-Lowry, acid is a substance which donate hydrogen ion and Base is a substance which accept hydrogen ion.
(d)
Answer to Problem 58A
Base
Explanation of Solution
The equation can be written as:
Equilibrium lies more towards reactant side. Therefore,
Chapter 16 Solutions
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