The reaction between C 2 H 2 ( g ) , F 2 ( g ) and the value of Δ S ∘ for this reaction is given. The value of S ∘ is to be calculated for C F 4 ( g ) . Concept introduction: Entropy ( Δ S ∘ ) is the measure of degree of disorder or randomness. The expression for Δ S ∘ is, Δ S ∘ = ∑ n p S ∘ ( product ) − ∑ n f S ∘ ( reactant )

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Technetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…

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Chapter 16, Problem 47E

Interpretation Introduction

Interpretation: The reaction between C2H2(g) , F2(g) and the value of ΔS∘ for this reaction is given. The value of S∘ is to be calculated for CF4(g) .

Concept introduction: Entropy (ΔS∘) is the measure of degree of disorder or randomness.

The expression for ΔS∘ is,

ΔS∘=∑npS∘(product)−∑nfS∘(reactant)

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Technetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…

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