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The CMOS inverter in Figure 16.21 is biased at
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MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
- Using the sine PWM method with the full bridge inverter below, it is desired to generate a voltage of 50 Hz on the serial RL load. A voltage of 120 V DC is applied to the input of the inverter circuit. Amplitude modulation rate ma -0.9 and frequency modulation rate mf -19. The resistance of the series RL load is 15 OHM and the coil inductance is 40 mH. a) What is the power drawn by the load resistor?b) What is the total harmonic distortion value (THD) of the load current?arrow_forwardThe load voltage waveform of a single phase full bridge inverter supplied from 300V DC voltage source is shown in below figure. Output frequency is 50HZ and the load consists of series R-L components. The load values are 20 and 0.04H, respectively. (Conduction interval for half period is 120°) 150 100 50 T -50 -100 -150 .002 .004 .006 .008 .01 .012 .014 .016 .018 .02 Time (sec) a. Calculate and draw the load current for the first two-period interval b. Calculate and draw the load current for the steady-state condition c. Find the RMS values of the load voltage and the load current d. Calculate and draw the voltage across the load inductance Calculate and draw the source current and find its average value e.arrow_forwardFor a stable operation a series resonant inverter circuit should be: Select one: Oa. Overdamped O b. Underdamped Oc. None of these Od. Critically damped Parallel resonant inverters are mostly known for the following features: Select one: a. The output current is dependent from the load. O b. The resonant circuit, load and switch are all in parallels Oc. It has the advantage of requiring small reactive components Od. None of thesearrow_forward
- A single phase bridge inverter has an RLC load with R = 20 ohms, L = 32 mH and C = 0.115 mF. The inverter frequency is fo = 60 Hz and DC input voltage is Vs = 110 V. The RMS magnitude of the 3rd and 5th harmonics of the output voltage are equal to: Select one: a. 46.7V and 25V b. 99V and 33V c. None of these d. 33V and 19.8Varrow_forwardFor an inverter with VIL = 0.46 V, VIH = 0.77 V, VOL= 0.08 V, and VOH = 1.2 V, find out the maximum value for the noise voltage in presence of which the inverter can work properly. Ans: 0.38 V.arrow_forwardThe load voltage waveform of a single phase full bridge inverter supplied from 300V DC voltage source is shown in below figure. Output frequency is 50HZ and the load consists of series R-L components. The load values are 2N and 0.04H, respectively. (Conduction interval for half period is 120°) 150 100 50 T -50 3 -100 -150 .002 .004 .006 .008 .014 ,02 .01 Time (sec) .012 .016 .018 a. Find the RMS values of the load voltage and the load current b. Calculate and draw the voltage across the load inductance c. Calculate and draw the source current and find its average valuearrow_forward
- 4arrow_forwardThe total rms output voltage of a single-phase bridge inverter operating from a nominal 200V DC supply is to be kept constant at 100V. If the supply voltage varies from 180 to 200V. Calculate : 1. 2. The range of conduction pulse widths (2d). For nominal input voltage find rms value of fundamental output voltage and rms value of 3rd harmonic in the output.arrow_forwardA single phase half bridge inverter is operating from a 25 V DC source and supplies power to resistive load. What is the distortion factor of fundamental output voltage?arrow_forward
- Nonearrow_forwardThe load voltage waveform of a single phase full bridge inverter supplied from 300V DC voltage source is shown in below figure. Output frequency is 50HZ and the load consists of series R-L components. The load values are 22 and 0.04H, respectively. (Conduction interval for half period is 120°) 150 100 50 T -50 3 -100 -150 .002 .004 .006 .008 .01 .012 .014 .016 .018 .02 Time (sec) a. Calculate and draw the load current for the first two-period interval b. Calculate and draw the load current for the steady-state conditionarrow_forwardI need especially graphics, thank you.arrow_forward
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