(a) Interpretation: The isomers: mesitylene ( 1, 3, 5-trimethylbenzene ) and p -ethyltoluene , using NMR spectroscopy are to be differentiated. Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 1

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 2

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 3

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 4

Question

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

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Answer 5

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 6

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 7

Chapter 16, Problem 16.6P

Interpretation Introduction

(a)

Interpretation:

The isomers: mesitylene(1, 3, 5-trimethylbenzene) and p-ethyltoluene, using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The isomers: 1-bromo-4-ethylbenzene and (2-bromoethyl)benzene(BrCH2CH2Ph), using NMR spectroscopy are to be differentiated.

Concept introduction:

The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 16 - Prob. 16.1P Ch. 16 - Prob. 16.2P Ch. 16 - Prob. 16.3P Ch. 16 - Prob. 16.4P Ch. 16 - Prob. 16.5P Ch. 16 - Prob. 16.6P Ch. 16 - Prob. 16.7P Ch. 16 - Prob. 16.8P Ch. 16 - Prob. 16.9P Ch. 16 - Prob. 16.10P

Solution Summary: The author explains that the number of NMR signal in a compound is equal to the amount of chemically non-equivalent protons present in that compound.

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Chapter 16 Solutions