
(a)
Interpretation:
The structures of dibromobenzene derivatives are to be drawn by assuming the correctness of Kekule structure of benzene.
Concept introduction:
Kekule structure is the representation of a compound by its Lewis structure. In this structure, the covalent bonds are shown for the bonded electron pairs. Melting point of a compound depends upon its molecular symmetry.
(b)
Interpretation:
The structures of dibromobenzene derivatives are to be assigned by assuming the correctness of Ladenburg structure of benzene.
Concept introduction:
Ladenburg benzene structure is also known as Prismane structure. The carbon and hydrogen atoms of a benzene molecule are represented as three prismane structures arranged in the form of a triangular prism.
(c)
Interpretation:
The mononitration products which were formed in the least amount are to be identified.
Concept introduction:
Nitration is a process in which a nitro group is substituted on the
(d)
Interpretation:
The differences in the spectra of dibromobenzene derivaties are to be stated.
Concept introduction:
The NMR spectroscopy is used to determine the number of equivalent and non equivalent carbon atoms and to identify the type of carbon atoms present in the compound.

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Chapter 16 Solutions
Organic Chemistry
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
- please help fill in the tablearrow_forwardAnswer F pleasearrow_forward4. Refer to the data below to answer the following questions: The octapeptide saralasin is a specific antagonist of angiotensin II. A derivative of saralasin is used therapeutically as an antihypertensive. Amino acid analysis of saralasin show the presence of the following amino acids: Ala, Arg, His, Pro, Sar, Tyr, Val, Val A.Sar is the abbreviation for sarcosine, N-methyl aminoethanoic acid. Draw the structure of sarcosine. B. N-Terminal analysis by the Edman method shows saralasin contains sarcosine at the N-terminus. Partial hydrolysis of saralasin with dilute hydrochloric acid yields the following fragments: Tyr-Val-His Sar-Arg-Val His-Pro-Ala Val-Tyr-Val Arg-Val-Tyr What is the structure of saralasin?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
