Concept explainers
(a)
Interpretation:
Out of
Concept Introduction:
The solubility product for an equilibrium reaction is defined as the product of ion concentration raised to power their
The precipitation takes place due to the different solubilities of the two ionic compounds. The compound which is more soluble will remains in the solution whereas less soluble compound precipitates first.
(b)
Interpretation:
The concentration of first anion species when second anion species starts to precipitate has to be calculated.
Concept Introduction:
The solubility product for an equilibrium reaction is defined as the product of ion concentration raised to power their stoichiometric coefficient. The symbol for solubility product is
Want to see the full answer?
Check out a sample textbook solutionChapter 15 Solutions
Chemistry: The Molecular Science
- Suppose that an aqueous solution is in equilibrium with solid calcium sulfate and solid barium sulfate. What are the concentrations of calcium ion and barium ion in the solution?arrow_forwardSome barium chloride is added to a solution that contains both K2SO4 (0.050 M) and Na3PO4 (0.020 M). (a) Which begins to precipitate first: the barium sulfate or the barium phosphate? (b) The concentration of the first anion species to precipitate, either the sulfate or phosphate, decreases as the precipitate forms. What is the concentration of the first species when the second begins to precipitate?arrow_forwardConsider 1.0 L of an aqueous solution that contains 0.10 M sulfuric acid to which 0.30 mole of barium nitrate is added. Assuming no change in volume of the solution, determine the pH, the concentration of barium ions in the final solution, and the mass of solid formed.arrow_forward
- 24. A solution of volume 0.500 L contains 1.68 g NH3 and 4.05 g (NH4)2SO4. (a) What is the pH of this solution? (b) If 0.88 g NaOH is added to the solution, what will be the pH? (c) How many milliliters of 12 M HCl must be added to 0.500 L of the original solution to change its pH to 9.00?arrow_forwardPrecipitation is the opposite of dissolution. Group of answer choices True Falsearrow_forwardThe Solubility Product Constant for manganese(II) carbonate is 1.8 × 10−¹¹ The molar solubility of manganese(II) carbonate in a water solution is M.arrow_forward
- An aqueous solution contains 0.28 M hydrofluoric acid. One Liter of this solution could be converted into a buffer by the addition of: (Assume that the volume remains constant as each substance is added.) O 0.139 mol NaOH 0.28 mol NaNO, 0.14 mol HNO, 0.29 mol HNO3 O 0.29 mol NaFarrow_forwardIn this assignment, you will determine the mass % of an unknown sample of baking soda (NaHCO3) by titrating it with an HCl solution of known concentration. The laboratory will open with a beaker on the stir plate with 1.5000 g of impure solid NaHCO3 and with sufficient water added to make the total volume 25.00 mL. The buret will be filled with 0.3015 M HCl. Pouring HCI until pH is 2. The volume in the buret went from 0 mL to 43 mL Question 1: Calculate the moles of HCl transferred during the titration. (number and unit) (Keep four significant digits in all of the calculations.) Question 2: How many moles of NaHCO3 are present in the sample? Question 3: What mass of NaHCO3 is present in the sample? Question 4: What percent of the original sample mass was NaHCO3?arrow_forwardWrite the precipitation reaction for ammonium bromide in aqueous solution: Is ammonium bromide considered soluble or not soluble ?arrow_forward
- (a) A 50.0 mL solution is prepared to be 1.29 M acetylsalicylic acid. In the first step, 8.55 mL of NaOH is titrated into the solution until the pH is exactly 5.0. What is the concentration of the titrant (NaOH)? (b) In the second step, enough 5.85 M nitric acid is added to the solution after the titration in part (a) is complete until the pH is one unit lower than the pKa of acetylsalicylic acid. What volume (mL) of nitric acid was added?arrow_forwardThe arsenate sample was treated using silver ion to form a precipitate, silver arsenate. It took exactly 25.0 mL of a silver ion solution to remove all of the arsenate. The concentration of the silver ion solution is given below. Calculate the number of moles of silver ion used. 0.102 M Ag+. B) .Calculate the number of moles of arsenic in the precipitate. The formula for the precipitate is given below. Ag3AsO4arrow_forwardwhat is the concentration of fluoride ions in barium fluoride in a saturated solution? The solubility constant is 1.7 x 10^-6arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning