Concept explainers
(a)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
(b)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
(c)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
(d)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
(e)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
(f)
Interpretation:
A balanced chemical equation for the equilibrium occurring when the given solute is added to water is to be stated and the
Concept Introduction:
In a saturated solution, the molar solubility of salt is used to determine the solubility product. The compounds which have high solubility product are more soluble in aqueous solution.
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Chapter 15 Solutions
Chemistry: The Molecular Science
- Hydrogen iodide gas decomposes to hydrogen gas and iodine gas: 2HI(g)H2(g)+I2(g)To determine the equilibrium constant of the system, identical one-liter glass bulbs are filled with 3.20 g of HI and maintained at a certain temperature. Each bulb is periodically opened and analyzed for iodine formation by titration with sodium thiosulfate, Na2S2O3. I2(aq)+2S2O32(aq)S4O62(aq)+2 I(aq)It is determined that when equilibrium is reached, 37.0 mL of 0.200 M Na2S2O3 is required to titrate the iodine. What is K at the temperature of the experiment?arrow_forwardTo a beaker with 500 mL of water are added 95 mg of Ba(NO3)2, 95 mg of Ca(NO3)2, and 100.0 mg of Na2CO3. After equilibrium is established, will there be • no precipitate? • a precipitate of BaCO3 only? • a precipitate of CaCO3 only? • a precipitate of both CaCO3 and BaCO3? Assume that the volume of the solution is still 500.0 mL after the addition of the salts.arrow_forwardAcrylic acid is used in the polymer industry in the production of acrylates. Its K, is 5.6 X 10“’. What is the pH of a 0.11 M solution of acrylic acid, CH2CHCOOH?arrow_forward
- Consider the system 4NH3(g)+3O2(g)2N2(g)+6H2O(l)H=1530.4kJ (a) How will the concentration of ammonia at equilibrium be affected by (1) removing O2(g)? (2) adding N2(g)? (3) adding water? (4) expanding the container? (5) increasing the temperature? (b) Which of the above factors will increase the value of K? Which will decrease it?arrow_forwardA small quantity of a soluble salt is placed in water. Equilibrium between dissolved and undissolved salt may or may not be attained. Explain.arrow_forwardWrite the expression for the equilibrium constant and calculate the partial pressure of CO2(g), given that Kp is 0.25 (at 427 C) for NaHCO3(s) NaOH(s) + CO2(g)arrow_forward
- Because barium sulfate is opaque to X-rays, it is suspended in water and taken internally to make the gastrointestinal tract visible in an X-ray photograph. Although barium ion is quite toxic, barium sulfate’s /Csp of 1.1 X 10-,<) gives it such low solubility' that it can be safely consumed. What is the molar solubility' of BaSO4. What is its solubility' in grams per 100 g of water?arrow_forwardWhat must be the concentration of chromate ion in order to precipitate strontium chromate, SrCrO4, from a solution that is 0.0034 M Sr2+?arrow_forwardSome barium chloride is added to a solution that contains both K2SO4 (0.050 M) and Na3PO4 (0.020 M). (a) Which begins to precipitate first: the barium sulfate or the barium phosphate? (b) The concentration of the first anion species to precipitate, either the sulfate or phosphate, decreases as the precipitate forms. What is the concentration of the first species when the second begins to precipitate?arrow_forward
- Construct the reaction table for mixing 22.0 mL of 0.190 M AgNO3 and 74.0 mL of 0.140 M K2CrO4. Enter the net ionic equation. Reaction Tabl ecation+anionprecipitate (a) What mass of precipitate forms? (b) What is the concentration of the excess reactant at equilibrium? (c) What is the concentration of the limiting reactant at equilibrium? (The answer is NOT zero. Please use Ksp to calculate this.)arrow_forwardGiven the solubility, calculate the solubility product constant (Ksp) of each salt at 25°C: (a) Ag2SO3, s = 4.6 ×10−3 g/L (b) Hg2I2, s = 1.5 ×10−7 g/L (c) Zn3(PO4)2, s = 5.9 × 10−5 g/Larrow_forward(4) A solution is made of a mixture of 0.500 M Calcium chloride and 0.0100 M iron (II) nitrate. The two metals are to be separated by precipitation by increasing the pH. (a) At what pH will the first metal begin to precipitate? (b) At what pH will 99.9% of the first metal be precipitated? (c) At what pH will the second metal begin to precipitate? (d) Can the metals be separated successfully?arrow_forward
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