Organic Chemistry (8th Edition)
8th Edition
ISBN: 9780134042282
Author: Paula Yurkanis Bruice
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 15, Problem 67P
Two products, A and B, are obtained from the reaction of 1-bromobutane with NH3. Compound A reacts with acetyl chloride to form C, and compound B reacts with acetyl chloride to form D. The IR spectra of C and D are shown. Identify A, B, C, and D.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Grignard reagent is a versatile tool in synthetic organic chemistry. Using bromocyclopentane as a starting material, show how a Grignard reagent, X, is synthesized.
Reaction of X with water produces compound Y while treatment in carbon dioxide followed by hydrolysis forms compound Z. 3-methyl-2butanone reacts with X and hydrolyses to yield compound AA. Draw the structural formulae of compounds Y, Z and AA and write the chemical equations respectively.
Identify products A and B from the given 1H NMR data.
Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?
Dehydration of 2,2,3,4,4,-pentamethyl-3-pentanol gives two alkenes A and B. Ozonolysis of A gives formaldehyde and 2,2,4,4-tetramethyl-3-
pentanone. Ozonolysis of B gave formaldehyde and 3,3,4,4-tetramethyl-2-pentanone. Identify and draw the structures of A and B, and
explain how B could be formed in the dehydration reaction.
Chapter 15 Solutions
Organic Chemistry (8th Edition)
Ch. 15.1 - The aromas of many flowers and fruits are due to...Ch. 15.1 - Name the following:Ch. 15.1 - Prob. 3PCh. 15.2 - Which is longer, the carbon-oxygen single bond in...Ch. 15.2 - There are three carbon-oxygen bonds in methyl...Ch. 15.2 - Prob. 6PCh. 15.4 - a. What is the product of the reaction of acetyl...Ch. 15.4 - What is the product of an acyl substitution...Ch. 15.5 - a. Which compound has the stretching vibration for...Ch. 15.5 - Using the pKa values listed in Table 15.1, predict...
Ch. 15.5 - Is the following statement true or false? If the...Ch. 15.6 - Starting with acetyl chloride, what neutral...Ch. 15.6 - Prob. 13PCh. 15.7 - Starting with methyl acetate, what neutral...Ch. 15.7 - We saw that it is necessary to use excess amine in...Ch. 15.7 - Prob. 17PCh. 15.7 - Which ester hydrolyzes more rapidly? a. methyl...Ch. 15.7 - a. state three factors that cause the uncatalyzed...Ch. 15.8 - Prob. 21PCh. 15.8 - Using the mechanism for the acid-catalyzed...Ch. 15.8 - Prob. 23PCh. 15.8 - Show the mechanism for the acid-catalyzed...Ch. 15.8 - Prob. 25PCh. 15.8 - Write the mechanism for the acid-catalyzed...Ch. 15.8 - Write the mechanism for the acid-catalyzed...Ch. 15.9 - Prob. 28PCh. 15.9 - Prob. 29PCh. 15.10 - Show how each of the following esters could he...Ch. 15.10 - Prob. 32PCh. 15.11 - Prob. 33PCh. 15.11 - Which of the following reactions leads to the...Ch. 15.12 - Prob. 35PCh. 15.12 - Prob. 36PCh. 15.13 - Prob. 37PCh. 15.14 - Prob. 38PCh. 15.14 - Prob. 39PCh. 15.15 - Prob. 40PCh. 15.15 - Which alkyl halides from the carboxylic acids...Ch. 15.16 - Prob. 43PCh. 15.16 - Prob. 44PCh. 15.16 - Prob. 45PCh. 15.17 - Prob. 46PCh. 15.18 - How could you synthesize the following compounds...Ch. 15 - Prob. 48PCh. 15 - Name the following:Ch. 15 - Prob. 50PCh. 15 - What compound are obtained from the fallowing...Ch. 15 - a. Rank the following esters in order of...Ch. 15 - Because bromocyclohexane is a secondary alkyl...Ch. 15 - a. Which compound would you expect to have a...Ch. 15 - How could you use 1H NMR spectroscopy to...Ch. 15 - Rank the following compounds in order of...Ch. 15 - Prob. 57PCh. 15 - Prob. 58PCh. 15 - Prob. 59PCh. 15 - A compound with molecular formula C5H10O2 gives...Ch. 15 - Prob. 61PCh. 15 - Prob. 62PCh. 15 - Prob. 63PCh. 15 - Prob. 64PCh. 15 - Prob. 65PCh. 15 - Prob. 66PCh. 15 - Two products, A and B, are obtained from the...Ch. 15 - Prob. 68PCh. 15 - Prob. 69PCh. 15 - Prob. 70PCh. 15 - Prob. 71PCh. 15 - Prob. 72PCh. 15 - When treated with an equivalent of methanol,...Ch. 15 - a. Identify the two products obtained from the...Ch. 15 - Prob. 75PCh. 15 - Prob. 76PCh. 15 - a. When a carboxylic acid is dissolved in...Ch. 15 - Prob. 78PCh. 15 - Identity the major and minor products of the...Ch. 15 - When a compound with molecular formula C11H14O2...Ch. 15 - Prob. 81PCh. 15 - Prob. 82PCh. 15 - Prob. 83PCh. 15 - The 1H NMR spectra for two esters with molecular...Ch. 15 - Show how the following compounds could be prepared...Ch. 15 - Prob. 86PCh. 15 - Prob. 87PCh. 15 - The intermediate shown here is formed during the...Ch. 15 - Prob. 89PCh. 15 - Propose a mechanism that accounts for the...Ch. 15 - Catalytic antibodies catalyze a reaction by...Ch. 15 - Prob. 92P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Identify products A and B from the given 1H NMR data.a. Treatment of CH2 = CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?b. Treatment of acetone [(CH3)2C = O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?arrow_forwardIdentify products A and B from the given 1H NMR data. a.Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3 H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A? b.Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1 H) ppm. What is the structure of B?arrow_forwardTreatment of a hydrocarbon A (molecular formula C9H18) with Br2 in the presence of light forms alkyl halides B and C, both having molecular formula C9H17Br. Reaction of either B or C with KOC(CH3)3 forms compound D (C9H16) as the major product. Ozonolysis of D forms cyclohexanone and acetone. Identify the structures of A–D.arrow_forward
- Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forwardTreatment of compound A (C8H17Br) with NaOCH2CH3 affords twoconstitutional isomers B and C. Ozonolysis of B affords CH2=O and(CH3CH2CH2)2C=O. Ozonolysis of C affords CH3CH2CH2COCH3 andCH3CH2CHO. What is the structure of A?arrow_forwardSketch and explain the IR, UV, mass, and NMR (1H and 13C) spectroscopy data of benzaldehyde.arrow_forward
- Sharpless epoxidation of allylic alcohol X forms compound Y. Treatment of Y with NaOH and C6H5SH in an alcohol–water mixture forms Z. Identify the structure of Y and draw a mechanism for the conversion of Y to Z. Account for the stereochemistry of the stereogenic centers in Z. Z has been used as an intermediate in the synthesis of chiral carbohydrates.arrow_forwardCompound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoningarrow_forwardReduction reaction of 1-phenylethanone with lithium aluminium hydride yields a racemic mixture of 1-phenylethanol. Use a mechanism to account for the formation of the racemic mixture. Assign stereochemistry of your products.arrow_forward
- Compound A with molecular formula C6H10 has two peaks in its 1H NMR spectrum, both of which are singlets (with ratio 9 : 1). Compound A reacts with an acidic aqueous solution containing mercuric sulfate to form compound B, which gives a positive iodoform test and has an 1H NMR spectrum that shows two singlets (with ratio 3 : 1). Identify A and B.arrow_forwardTreatment of compound E (molecular formula C4H8O2) with excessCH3CH2MgBr yields compound F (molecular formula C6H14O) afterprotonation with H2O. E shows a strong absorption in its IR spectrum at1743 cm−1. F shows a strong IR absorption at 3600−3200 cm−1. The 1HNMR spectral data of E and F are given. What are the structures of E andF?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppm Compound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4H), and 1.55 (singlet, 1 H) ppmarrow_forwardDehydration of 2,2,3,4,4-pentamethyl-3-pentanol gave two alkenes A and B. Ozonolysis of the lower boiling alkene A gave formaldehyde (H2C= O) and 2,2,4,4-tetramethyl-3- pentanone. Ozonolysis of B gave formaldehyde and 3,3,4,4-tetramethyl-2-pentanone. Identify A and B, and suggest an explanation for the formation of B in the dehydration reaction.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
IR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=_TmevMf-Zgs;License: Standard YouTube License, CC-BY