Chapter 15, Problem 63AE

Interpretation Introduction

Interpretation:

Whether solution formed when $\text{380 mL}$ of $\text{0}\text{.35 M Ba}{\left(\text{OH}\right)}_2$ is added to $\text{500}\text{.0 mL}$ of $\text{0}\text{.65 }M\text{ HCl}$ is acidic, basic or neutral and $\text{pH}$ has to be calculated.

Concept Introduction:

The formula to calculate molar mass from number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

The expression to evaluate $\text{pH}$ is as follows:

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$