Chapter 15, Problem 68AE

Interpretation Introduction

Interpretation:

Whether solution formed $\text{425 mL}$ of $\text{0}{\text{.94 M H}}_2{\text{SO}}_{\text{4}}$ is added to $\text{750}\text{.0 mL}$ of $\text{0}\text{.83 }M\text{ NaOH}$  is acidic, basic or neutral and $\text{pH}$ of solution thus formed has to be calculated.

Concept Introduction:

The formula to calculate molar mass from number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

The expression to evaluate $\text{pH}$ is as follows:

  $\text{pH}=-\log \left[{\text{H}}^{+}\right]$