Mechanics of Materials, 7th Edition
7th Edition
ISBN: 9780073398235
Author: Ferdinand P. Beer, E. Russell Johnston Jr., John T. DeWolf, David F. Mazurek
Publisher: McGraw-Hill Education
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Chapter 1.5, Problem 37P
A steel loop ABCD of length 5 ft and of
Fig. P1.37
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12 in.
E
12 in.
A steel loop ABCD of length 5 ft and of -in. diameter is placed as
shown around a l-in.-diameter aluminum rod AC. Cables BE and DF,
each of -in. diameter, are used to apply the load Q. Knowing that the
ultimate strength of the steel used for the loop and the cables is 70 ksi,
and that the ultimate strength of the aluminum used for the rod is 38 ksi,
determine the largest load Q that can be applied if an overall factor of
safety of 3 is desired.
9 in.
1 in.
9 in.
in.
응 in.
F
An annular washer distributes the load P applied to a steel rod to a timber support.
The rod's diameter is 22 mm, and the washer's inner diameter is 25 mm, which is
larger than the hole's permissible outer diameter. Knowing that the axial normal stress
in the steel rod is 35 MPa and the average bearing stress between the washer and the
timber must not exceed 5 MPa, examine the smallest allowed outer diameter, d, of the
washer.
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+22 mm
P
Figure 4
Three wires are used to suspend the plate shown. Aluminum wires of 18-in. diameter are used at A and Bwhile a steel wire of 112-in. diameter is used at C. Knowing that the allowable stress for aluminum (Ea510.4 3 106 psi) is 14 ksi and that the allowable stress for steel (Es529 3 106 psi) is 18 ksi, determine the maximum load P that can be applied
Chapter 1 Solutions
Mechanics of Materials, 7th Edition
Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - A strain gage located at C on the surface of bone...Ch. 1.2 - Two brass rods AB and BC, each of uniform...Ch. 1.2 - Each of the four vertical links has an 8 36-mm...Ch. 1.2 - Link AC has a uniform rectangular cross section 18...Ch. 1.2 - Three forces, each of magnitude P = 4 kN, are...Ch. 1.2 - Link BD consists of a single bar 1 in. wide and 12...
Ch. 1.2 - For the Pratt bridge truss and loading shown,...Ch. 1.2 - The frame shown consists of four wooden members,...Ch. 1.2 - An aircraft tow bar is positioned by means of a...Ch. 1.2 - Two hydraulic cylinders are used to control the...Ch. 1.2 - Determine the diameter of the largest circular...Ch. 1.2 - Two wooden planks, each 12 in. thick and 9 in....Ch. 1.2 - When the force P reached 1600 lb, the wooden...Ch. 1.2 - A load P is applied to a steel rod supported as...Ch. 1.2 - The axial force in the column supporting the...Ch. 1.2 - Three wooden planks are fastened together by a...Ch. 1.2 - A 40-kN axial load is applied to a short wooden...Ch. 1.2 - An axial load P is supported by a short W8 40...Ch. 1.2 - Link AB, of width b = 2 in. and thickness t=14...Ch. 1.2 - Determine the largest load P that can be applied...Ch. 1.2 - Knowing that = 40 and P = 9 kN, determine (a) the...Ch. 1.2 - The hydraulic cylinder CF, which partially...Ch. 1.2 - For the assembly and loading of Prob. 1.7,...Ch. 1.2 - Two identical linkage-and-hydraulic-cylinder...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - The 1.4-kip load P is supported by two wooden...Ch. 1.5 - Two wooden members of uniform cross section are...Ch. 1.5 - A centric load P is applied to the granite block...Ch. 1.5 - A 240-kip load P is applied to the granite block...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel loop ABCD of length 5 ft and of 38-in....Ch. 1.5 - Link BC is 6 mm thick, has a width w = 25 mm, and...Ch. 1.5 - Link BC is 6 mm thick and is made of a steel with...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Link AB is to be made of a steel for which the...Ch. 1.5 - Two wooden members are joined by plywood splice...Ch. 1.5 - For the joint and loading of Prob. 1.43, determine...Ch. 1.5 - Three 34-in.-diameter steel bolts are to be used...Ch. 1.5 - Three steel bolts are to be used to attach the...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A steel plate 14 in. thick is embedded in a...Ch. 1.5 - Determine the factor of safety for the cable...Ch. 1.5 - Link AC is made of a steel with a 65-ksi ultimate...Ch. 1.5 - Solve Prob. 1.51, assuming that the structure has...Ch. 1.5 - Each of the two vertical links CF connecting the...Ch. 1.5 - Solve Prob. 1.53, assuming that the pins at C and...Ch. 1.5 - In the structure shown, an 8-mm-diameter pin is...Ch. 1.5 - In an alternative design for the structure of...Ch. 1.5 - Prob. 57PCh. 1.5 - The Load and Resistance Factor Design method is to...Ch. 1 - In the marine crane shown, link CD is known to...Ch. 1 - Two horizontal 5-kip forces are applied to pin B...Ch. 1 - For the assembly and loading of Prob. 1.60,...Ch. 1 - Two steel plates are to be held together by means...Ch. 1 - A couple M of magnitude 1500 N m is applied to...Ch. 1 - Knowing that link DE is 18 in. thick and 1 in....Ch. 1 - A 58-in.-diameter steel rod AB is fitted to a...Ch. 1 - In the steel structure shown, a 6-mm-diameter pin...Ch. 1 - Prob. 67RPCh. 1 - A force P is applied as shown to a steel...Ch. 1 - The two portions of member AB are glued together...Ch. 1 - The two portions of member AB are glued together...
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- 5. The load P applied to a steel rod is distributed to a timber support by an annular washer. The diameter of the rod is 22 mm and the inner diameter of the washer is 25 mm, which is slightly larger than the diameter of the hole. Determine the smallest allowable outer diameter d of the washer, knowing that the axial normal stress in the steel rod is 35 MPa and the average bearing stress between the washer and the timber must not exceed 5 MPa. - 22 mmarrow_forward1. A steel plate 5 /16 in. thick is embedded in a horizontal concrete slab and is used to anchor a high- strength vertical cable as shown. The diameter of the hole in the plate is 3 /4 in., the ultỉmate strength of the steel used is 36 ksi, and the ultimate bonding stress between plate and concrete is 300 psi. Knowing that a factor of safety of 3.60 is desired when P=2.5 kips, determine (a) the required width a of the plate, (b) the minimum depth b to which a plate of that width should be embedded in the concrete slab. (Neglect the normal stresses between the concrete and the bottom edge of the plate.arrow_forward2. The gray plastic block shown is bonded to a fixed base and to a horizontal rigid plate (black dotted outline) to which a force P is applied. Knowing that the plastic used has G= 50 ksi, determine the movement of the plate in the direction of the applied load when P =9 kips. Express your answer as a value with units. 3.5 in. 5.5 in. 2.2 in.arrow_forward
- 1.55 In the structure shown, an 8-mm-diameter pin is used at A, and 12-mm-diameter pins are used at B and D. Knowing that the ulti- mate shearing stress is 100 MPa at all connections and that the ultimate normal stress is 250 MPa in each of the two links joining B and D, determine the allowable load P if an overall factor of safety of 3.0 is desired. Тоp view 200 mm +180 mm - 12 mm 8 mm A В C A 20 mm P 8 mm 8 mm - DO 12 mm - Front view Side view Fig. P1.55arrow_forwardKnowing that, for the plate shown, the allowable stress is 136 MPa, determine the maximum allowable value of the centric axial load P. 15 mm 20 mm 100 mm 50 mm KN. The maximum allowable value of the centric axial load P isarrow_forwardOnly 1.53 plzarrow_forward
- please answer number 4.Mech 222- mechanics of deformable bodies:please give detailed solutions and correct answers.i will report to bartleby those tutors who will give incorrect answers.arrow_forward16 The length of the 32-in.-diameter steel wire CD has been adjusted so that with no load applied, a gap of in. exists between the end B of the rigid beam ACB and a contact point E. Knowing that E = 29 × 106 psi, determine where a 50-lb block should be placed on the beam to cause contact between B and E.arrow_forwardTwo gage marks are placed exactly 250 mm apart on a 12-mm-diameter aluminum rod with E5 73 GPa and an ultimate strength of 140 MPa. Knowing that the distance between the gage marks is 250.28 mm after a load is applied, determine (a) the stress in the rod, (b) the factor of safety.arrow_forward
- A square aluminum bar should not stretch more than 1.4 mm when it is subjected to a tensile load.Knowing that E = 70 GPa and that the allowable tensile strength is 120 MPa, determine the maximumallowable length.arrow_forwardTwo gage marks are placed exactly 10 in. apart on a 1⁄2-in.-diameter aluminum rod with E = 10.1 x 106 psi and an ultimate strength of 16 ksi. Knowing that the distance between the gage marks is 10.009 in. after a load isapplied, determine (a) the stress in the rod, (b) the factor of safety, (c) the corresponding normal stress in thewire.arrow_forwardTwo loads are applied to the bracket BCD as shown. (a) Knowing that the control rod AB is to be made of a steel having an ultimate normal stress of 600 MPa, determine the diameter of the rod for which the factor of safetywith respect to failure will be 3.3. (b) The pin at C is to be made of a steelhaving an ultimate shearing stress of 350 MPa. Determine the diameter ofthe pin C for which the factor of safety with respect to shear will also be 3.3.(c) Determine the required thickness of the bracket supports at C, knowingthat the allowable bearing stress of the steel used is 300 MPa.arrow_forward
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EVERYTHING on Axial Loading Normal Stress in 10 MINUTES - Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=jQ-fNqZWrNg;License: Standard YouTube License, CC-BY