
(a)
Interpretation:
IUPAC name has to be given for all unbranched-chain saturated compounds that can be named as hexanals.
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula. The main difference lies in the way the atoms are arranged in the structure. Isomers have different chemical and physical properties even when they have same molecular formula. This is known as Isomerism.
If there is difference only in the connectivity of the atoms in the molecule, then it is known as constitutional isomerism. The isomers are known as constitutional isomers. They will have same molecular formula and same
For naming an aldehyde in
IUPAC rules for naming an aldehyde:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-al”.
- • Numbering is done in a way that the carbonyl group is designated as number 1. This is not indicated in the part of the name because for aldehyde, the carbonyl carbon is always numbered 1.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • If the carbonyl functional group is attached to a ring of carbon atoms, the ring is named and “-carbaldehyde” is added as suffix.
(b)
Interpretation:
IUPAC name for all possible saturated unbranched ketones that are named as hexanones has to be given.
Concept Introduction:
Isomers are the compounds that have same molecular formula but different structural formula. The main difference lies in the way the atoms are arranged in the structure. Isomers have different chemical and physical properties even when they have same molecular formula. This is known as Isomerism.
If there is difference only in the connectivity of the atoms in the molecule, then it is known as constitutional isomerism. The isomers are known as constitutional isomers. They will have same molecular formula and same functional group, but they differ in the connectivity between the atoms in the molecule.
Aldehydes and ketones have constitutional isomers. Functional group isomerism exists between aldehyde and ketones. Aldehydes and ketones that have same degree of saturation and same number of carbon atoms are functional group isomers. In aldehyde, skeletal isomerism is possible where the group attached to the carbonyl carbon atom connectivity is changed. In ketones positional isomerism is possible where the carbonyl group is moved within the carbon chain.
For naming a ketone in IUPAC nomenclature, the suffix “-one” is added to the parent alkane name.
IUPAC rules for naming a ketone:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-one”.
- • Numbering is done in a way that the carbonyl group gets the least numbering. The position of the carbonyl group is indicated in the name.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • Cyclic ketones are named by adding the suffix “-one” to the name of the carbon ring. The substituents are numbered so that it gets the least numbering starting from the carbonyl group that is given the number 1.

Want to see the full answer?
Check out a sample textbook solution
Chapter 15 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- ||| 7:47 ull 57% ← Problem 19 of 48 Submit Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this carbocation rearrangement. Include all lone pairs and charges as appropriate. H 1,2-alkyl shift +arrow_forwardWould the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardBelow is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 5th attempt Please draw all four bonds at chiral centers. Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers. 1000 4th attempt Feedback Please draw all four bonds at chiral centers. 8. R5 HO: See Periodic Table See Hint H Cl Br Jid See Periodic Table See Hintarrow_forward
- Show that a molecule with configuration π4 has a cylindrically symmetric electron distribution. Hint: Let the π orbitals be equal to xf and yf, where f is a function that depends only on the distance from the internuclear axis.arrow_forward(a) Verify that the lattice energies of the alkali metal iodides are inversely proportional to the distances between the ions in MI (M = alkali metal) by plotting the lattice energies given below against the internuclear distances dMI. Is the correlation good? Would a better fit be obtained by plotting the lattice energies as a function of (1 — d*/d)/d, as theoretically suggested, with d* = 34.5 pm? You must use a standard graphing program to plot the graph. It generates an equation for the line and calculates a correlation coefficient. (b) From the graph obtained in (a), estimate the lattice energy of silver iodide. (c) Compare the results of (b) with the experimental value of 886 kJ/mol. If they do not agree, explain the deviation.arrow_forwardCan I please get help with #3 & 4? Thanks you so much!arrow_forward
- A solution consisting of 0.200 mol methylbenzene, C,H,CH,, in 500. g of nitrobenzene, CH,NO₂, freezes at 3.2°C. Pure nitrobenzene freezes at 6.0°C. The molal freezing point constant of nitrobenzene is _ °C/m. a) 2.8 b) 3.2 c) 5.6 d) 7.0 e) 14.0arrow_forwardBelow is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide ("OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 2nd attempt Please draw all four bonds at chiral centers. 0 D Draw the missing curved arrow notation. Add lone pairs of electrons and nonzero formal charges. + 노 V 1st attempt Feedback Please draw all four bonds at chiral centers. See Periodic Table See Hint F P 41 H Br See Periodic Table See Hint H Larrow_forwardHow close are the Mulliken and Pauling electronegativity scales? (a) Now that the ionization energies and electron affinities have been defined, calculate the Mulliken and Pauling electronegativities for C, N, O and F. Compare them. (Make the necessary adjustments to the values, such as dividing the ionization energies and electron affinities by 230kj/mol) (b) Plot both sets of electronegativities against atomic number (use the same graph). (c) Which scale depends most consistently on position in the Periodic Table?arrow_forward
- Below is the SN2 reaction between 2-bromopropane and iodide (I). Draw the mechanism arrows in the first box to reflect electron movements. In both boxes, add lone pairs of electrons and nonzero formal charges. 4th attempt Feedback 3rd attempt Feedback 1 -Br H :Bri :Br: ili See Periodic Table See Hint ini See Periodic Table See Hintarrow_forwardWhen 4-chloro-1-butanol is placed in sodium hydride, a cyclization reaction occurs. 3rd attempt 2 HO NaH CI D Draw the curved arrow notation to form the intermediate. 4 2 H₂ See Periodic Table See Hint =arrow_forwardSketch, qualitatively, the potential energy curves of the N-N bond of N2H4, N2 and N3- graph. Explain why the energy at the minimum of each curve is not the same.arrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningPrinciples of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning





