Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
7th Edition
ISBN: 9781305717534
Author: H. Stephen Stoker
Publisher: Cengage Learning
Question
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Chapter 15, Problem 15.22EP

(a)

Interpretation Introduction

Interpretation:

Structural formula for the given aldehyde has to be drawn.

Concept Introduction:

Structure of the aldehyde can be drawn from the IUPAC name.  In the IUPAC name, the parent chain of carbon atom can be identified and then the substituents present in it can also be identified.  With these information, the structure for the given compound can be drawn.  In an aldehyde the counting has to be always from the carbonyl carbon that is given the number 1.

The structural representation of organic compound can be done in 2D and 3D.  In two-dimensional representation, there are four types of representation in which an organic compound can be drawn.  They are,

  • • Expanded structural formula
  • • Condensed structural formula
  • • Skeletal structural formula
  • • Line-angle structural formula

Structural formula which shows all the atoms in a molecule along with all the bonds that is connecting the atoms present in the molecule is known as Expanded structural formula.

Structural formula in which grouping of atoms are done and in which the central atoms along with the other atoms are connected to them are treated as group is known as Condensed structural formula.

Structural formula that shows the bonding between carbon atoms alone in the molecule ignoring the hydrogen atoms being shown explicitly is known as Skeletal structural formula.

Structural formula where a line represent carbon‑carbon bond and the carbon atom is considered to be present in each point and the end of lines is known as Line-angle structural formula.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 1

(a)

Expert Solution
Check Mark

Answer to Problem 15.22EP

The structural formula for 2-methylpentanal is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 2

Explanation of Solution

The given name of the compound is 2-methylpentanal.  From the name it is understood that the parent carbon chain is pentane and it contains five carbon atoms.  The parent chain can be drawn as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 3

From the name of the given aldehyde, the substituents that are present can be identified.  In this case, the substituent is a methyl group on second carbon atom.  The first carbon atom has to be the carbonyl carbon atom as the given compound is an aldehyde.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 4

Carbon atom has a valence of four.  Hence, carbon atom can form four covalent bonds.  The remaining bonds are satisfied by hydrogen atom.  The structure is obtained as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 5

Conclusion

Structural formula for the given aldehyde is drawn.

(b)

Interpretation Introduction

Interpretation:

Structural formula for the given aldehyde has to be drawn.

Concept Introduction:

Structure of the aldehyde can be drawn from the IUPAC name.  In the IUPAC name, the parent chain of carbon atom can be identified and then the substituents present in it can also be identified.  With these information, the structure for the given compound can be drawn.  In an aldehyde the counting has to be always from the carbonyl carbon that is given the number 1.

The structural representation of organic compound can be done in 2D and 3D.  In two-dimensional representation, there are four types of representation in which an organic compound can be drawn.  They are,

  • • Expanded structural formula
  • • Condensed structural formula
  • • Skeletal structural formula
  • • Line-angle structural formula

Structural formula which shows all the atoms in a molecule along with all the bonds that is connecting the atoms present in the molecule is known as Expanded structural formula.

Structural formula in which grouping of atoms are done and in which the central atoms along with the other atoms are connected to them are treated as group is known as Condensed structural formula.

Structural formula that shows the bonding between carbon atoms alone in the molecule ignoring the hydrogen atoms being shown explicitly is known as Skeletal structural formula.

Structural formula where a line represent carbon‑carbon bond and the carbon atom is considered to be present in each point and the end of lines is known as Line-angle structural formula.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 6

(b)

Expert Solution
Check Mark

Answer to Problem 15.22EP

The structural formula for 4-ethylhexanal is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 7

Explanation of Solution

The given name of the compound is 4-ethylhexanal.  From the name it is understood that the parent carbon chain is hexane and it contains six carbon atoms.  The parent chain can be drawn as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 8

From the name of the given aldehyde, the substituents that are present can be identified.  In this case, the substituent is an ethyl group on fourth carbon atom.  The first carbon atom has to be the carbonyl carbon atom as the given compound is an aldehyde.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 9

Carbon atom has a valence of four.  Hence, carbon atom can form four covalent bonds.  The remaining bonds are satisfied by hydrogen atom.  The structure is obtained as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 10

Conclusion

Structural formula for the given aldehyde is drawn.

(c)

Interpretation Introduction

Interpretation:

Structural formula for the given aldehyde has to be drawn.

Concept Introduction:

Structure of the aldehyde can be drawn from the IUPAC name.  In the IUPAC name, the parent chain of carbon atom can be identified and then the substituents present in it can also be identified.  With these information, the structure for the given compound can be drawn.  In an aldehyde the counting has to be always from the carbonyl carbon that is given the number 1.

The structural representation of organic compound can be done in 2D and 3D.  In two-dimensional representation, there are four types of representation in which an organic compound can be drawn.  They are,

  • • Expanded structural formula
  • • Condensed structural formula
  • • Skeletal structural formula
  • • Line-angle structural formula

Structural formula which shows all the atoms in a molecule along with all the bonds that is connecting the atoms present in the molecule is known as Expanded structural formula.

Structural formula in which grouping of atoms are done and in which the central atoms along with the other atoms are connected to them are treated as group is known as Condensed structural formula.

Structural formula that shows the bonding between carbon atoms alone in the molecule ignoring the hydrogen atoms being shown explicitly is known as Skeletal structural formula.

Structural formula where a line represent carbon‑carbon bond and the carbon atom is considered to be present in each point and the end of lines is known as Line-angle structural formula.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 11

(c)

Expert Solution
Check Mark

Answer to Problem 15.22EP

The structural formula for 3,3-dimethylhexanal is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 12

Explanation of Solution

The given name of the compound is 3,3-dimethylhexanal.  From the name it is understood that the parent carbon chain is hexane and it contains six carbon atoms.  The parent chain can be drawn as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 13

From the name of the given aldehyde, the substituents that are present can be identified.  In this case, the substituents are two methyl groups on third carbon atom.  The first carbon atom has to be the carbonyl carbon atom as the given compound is an aldehyde.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 14

Carbon atom has a valence of four.  Hence, carbon atom can form four covalent bonds.  The remaining bonds are satisfied by hydrogen atom.  The structure is obtained as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 15

Conclusion

Structural formula for the given aldehyde is drawn.

(d)

Interpretation Introduction

Interpretation:

Structural formula for the given aldehyde has to be drawn.

Concept Introduction:

Structure of the aldehyde can be drawn from the IUPAC name.  In the IUPAC name, the parent chain of carbon atom can be identified and then the substituents present in it can also be identified.  With these information, the structure for the given compound can be drawn.  In an aldehyde the counting has to be always from the carbonyl carbon that is given the number 1.

The structural representation of organic compound can be done in 2D and 3D.  In two-dimensional representation, there are four types of representation in which an organic compound can be drawn.  They are,

  • • Expanded structural formula
  • • Condensed structural formula
  • • Skeletal structural formula
  • • Line-angle structural formula

Structural formula which shows all the atoms in a molecule along with all the bonds that is connecting the atoms present in the molecule is known as Expanded structural formula.

Structural formula in which grouping of atoms are done and in which the central atoms along with the other atoms are connected to them are treated as group is known as Condensed structural formula.

Structural formula that shows the bonding between carbon atoms alone in the molecule ignoring the hydrogen atoms being shown explicitly is known as Skeletal structural formula.

Structural formula where a line represent carbon‑carbon bond and the carbon atom is considered to be present in each point and the end of lines is known as Line-angle structural formula.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 16

(d)

Expert Solution
Check Mark

Answer to Problem 15.22EP

The structural formula for 2,3-dibromopropanal is,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 17

Explanation of Solution

The given name of the compound is 2,3-dibromopropanal.  From the name it is understood that the parent carbon chain is propane and it contains three carbon atoms.  The parent chain can be drawn as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 18

From the name of the given aldehyde, the substituents that are present can be identified.  In this case, the substituents are two bromine atoms, each on second carbon atom and third carbon atom.  The first carbon atom has to be the carbonyl carbon atom as the given compound is an aldehyde.

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 19

Carbon atom has a valence of four.  Hence, carbon atom can form four covalent bonds.  The remaining bonds are satisfied by hydrogen atom.  The structure is obtained as shown below,

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card, Chapter 15, Problem 15.22EP , additional homework tip 20

Conclusion

Structural formula for the given aldehyde is drawn.

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Chapter 15 Solutions

Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card

Ch. 15.1 - Prob. 1QQCh. 15.1 - Prob. 2QQCh. 15.2 - Prob. 1QQCh. 15.2 - Prob. 2QQCh. 15.2 - Prob. 3QQCh. 15.3 - Prob. 1QQCh. 15.3 - Prob. 2QQCh. 15.3 - Prob. 3QQCh. 15.4 - Prob. 1QQCh. 15.4 - Prob. 2QQ
Ch. 15.4 - Prob. 3QQCh. 15.4 - Prob. 4QQCh. 15.4 - Prob. 5QQCh. 15.5 - Prob. 1QQCh. 15.5 - Prob. 2QQCh. 15.5 - Prob. 3QQCh. 15.5 - Prob. 4QQCh. 15.5 - Prob. 5QQCh. 15.6 - Prob. 1QQCh. 15.6 - Prob. 2QQCh. 15.6 - Prob. 3QQCh. 15.7 - Prob. 1QQCh. 15.7 - Prob. 2QQCh. 15.8 - Prob. 1QQCh. 15.8 - Prob. 2QQCh. 15.9 - Prob. 1QQCh. 15.9 - Prob. 2QQCh. 15.10 - Prob. 1QQCh. 15.10 - Prob. 2QQCh. 15.10 - Prob. 3QQCh. 15.10 - Prob. 4QQCh. 15.11 - Prob. 1QQCh. 15.11 - Prob. 2QQCh. 15.11 - Prob. 3QQCh. 15.11 - Prob. 4QQCh. 15.11 - Prob. 5QQCh. 15.12 - Prob. 1QQCh. 15.12 - Prob. 2QQCh. 15 - Prob. 15.1EPCh. 15 - Prob. 15.2EPCh. 15 - Prob. 15.3EPCh. 15 - In terms of polarity, which carbonyl group atom...Ch. 15 - Prob. 15.5EPCh. 15 - What is the geometrical arrangement for the atoms...Ch. 15 - Prob. 15.7EPCh. 15 - Prob. 15.8EPCh. 15 - Prob. 15.9EPCh. 15 - Prob. 15.10EPCh. 15 - Prob. 15.11EPCh. 15 - Classify each of the following structures as an...Ch. 15 - Prob. 15.13EPCh. 15 - Prob. 15.14EPCh. 15 - Prob. 15.15EPCh. 15 - Prob. 15.16EPCh. 15 - Prob. 15.17EPCh. 15 - Prob. 15.18EPCh. 15 - Prob. 15.19EPCh. 15 - Prob. 15.20EPCh. 15 - Prob. 15.21EPCh. 15 - Prob. 15.22EPCh. 15 - Prob. 15.23EPCh. 15 - Prob. 15.24EPCh. 15 - Prob. 15.25EPCh. 15 - Prob. 15.26EPCh. 15 - Prob. 15.27EPCh. 15 - Prob. 15.28EPCh. 15 - Prob. 15.29EPCh. 15 - Prob. 15.30EPCh. 15 - Prob. 15.31EPCh. 15 - Prob. 15.32EPCh. 15 - Prob. 15.33EPCh. 15 - Prob. 15.34EPCh. 15 - Prob. 15.35EPCh. 15 - Prob. 15.36EPCh. 15 - Prob. 15.37EPCh. 15 - Prob. 15.38EPCh. 15 - Prob. 15.39EPCh. 15 - Prob. 15.40EPCh. 15 - Draw a structural formula for each of the...Ch. 15 - Prob. 15.42EPCh. 15 - Prob. 15.43EPCh. 15 - Prob. 15.44EPCh. 15 - Prob. 15.45EPCh. 15 - Prob. 15.46EPCh. 15 - Prob. 15.47EPCh. 15 - Prob. 15.48EPCh. 15 - Prob. 15.49EPCh. 15 - Prob. 15.50EPCh. 15 - Prob. 15.51EPCh. 15 - Prob. 15.52EPCh. 15 - Prob. 15.53EPCh. 15 - Prob. 15.54EPCh. 15 - Prob. 15.55EPCh. 15 - Prob. 15.56EPCh. 15 - Prob. 15.57EPCh. 15 - Prob. 15.58EPCh. 15 - Prob. 15.59EPCh. 15 - Prob. 15.60EPCh. 15 - Prob. 15.61EPCh. 15 - Prob. 15.62EPCh. 15 - Prob. 15.63EPCh. 15 - Prob. 15.64EPCh. 15 - Prob. 15.65EPCh. 15 - Prob. 15.66EPCh. 15 - Prob. 15.67EPCh. 15 - Which member in each of the following pairs of...Ch. 15 - Prob. 15.69EPCh. 15 - Prob. 15.70EPCh. 15 - Prob. 15.71EPCh. 15 - Prob. 15.72EPCh. 15 - Prob. 15.73EPCh. 15 - Prob. 15.74EPCh. 15 - Prob. 15.75EPCh. 15 - Prob. 15.76EPCh. 15 - Prob. 15.77EPCh. 15 - Prob. 15.78EPCh. 15 - Prob. 15.79EPCh. 15 - What is the chemical formula of the inorganic...Ch. 15 - Prob. 15.81EPCh. 15 - Which of the following compounds would react with...Ch. 15 - Prob. 15.83EPCh. 15 - Prob. 15.84EPCh. 15 - Which of the three compounds pentanal,...Ch. 15 - Prob. 15.86EPCh. 15 - Prob. 15.87EPCh. 15 - Prob. 15.88EPCh. 15 - Prob. 15.89EPCh. 15 - Prob. 15.90EPCh. 15 - Prob. 15.91EPCh. 15 - Prob. 15.92EPCh. 15 - Which carbon atom is the hemiacetal carbon atom in...Ch. 15 - Prob. 15.94EPCh. 15 - Prob. 15.95EPCh. 15 - Prob. 15.96EPCh. 15 - Prob. 15.97EPCh. 15 - Prob. 15.98EPCh. 15 - Prob. 15.99EPCh. 15 - Prob. 15.100EPCh. 15 - Prob. 15.101EPCh. 15 - Prob. 15.102EPCh. 15 - Prob. 15.103EPCh. 15 - Prob. 15.104EPCh. 15 - Prob. 15.105EPCh. 15 - Prob. 15.106EPCh. 15 - Prob. 15.107EPCh. 15 - Prob. 15.108EPCh. 15 - Prob. 15.109EPCh. 15 - Prob. 15.110EPCh. 15 - Prob. 15.111EPCh. 15 - Prob. 15.112EPCh. 15 - Prob. 15.113EPCh. 15 - Prob. 15.114EPCh. 15 - Prob. 15.115EPCh. 15 - Prob. 15.116EPCh. 15 - Prob. 15.117EPCh. 15 - Prob. 15.118EP
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