General, Organic, & Biological Chemistry
General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of th…
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotat…
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Chapter 15, Problem 15.26P
Interpretation Introduction

(a)

Interpretation:

A baseball glove should be classified as chiral or achiral.

Concept Introduction:

Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.

General, Organic, & Biological Chemistry, Chapter 15, Problem 15.26P , additional homework tip 1

In the above diagram, where C is the chiral center/ asymmetric carbon center.

A, B, D, E are four different functional groups.

Interpretation Introduction

(b)

Interpretation:

A scissor should be classified as chiral or achiral.

Concept Introduction:

Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.

General, Organic, & Biological Chemistry, Chapter 15, Problem 15.26P , additional homework tip 2

In the above diagram, where C is the chiral center/ asymmetric carbon center.

A, B, D, E are four different functional groups.

Interpretation Introduction

(c)

Interpretation:

A glass of water should be classified as chiral or achiral.

Concept Introduction:

Chirality is the presence of an asymmetric carbon center in a molecule and a molecule which contains a chiral center cannot superimpose on its mirror image. To consider as chiral, molecule or object and its mirror image should not superimpose. To consider as achiral, molecule or object and its mirror image should be superimposed with each other.

General, Organic, & Biological Chemistry, Chapter 15, Problem 15.26P , additional homework tip 3

In the above diagram, where C is the chiral center/ asymmetric carbon center.

A, B, D, E are four different functional groups.

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Questions 4 and 5
For a titration of 40.00 mL of 0.0500 M oxalic acid H2C2O4 with 0.1000 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin;2) 15 mL; 3) 20 mL; 4) 25 mL; 5) 40 mL; 6) 50 mL. Ka1 = 5.90×10^-2, Ka2 = 6.50×10^-5 for oxalic acid.
Predict the major organic product(s), if any, of the following reactions.  Assume all reagents are in excess unless otherwise indicated.

Chapter 15 Solutions

General, Organic, & Biological Chemistry

Ch. 15.1 - Prob. 15.1PCh. 15.1 - For trans-2-hexene: (a) draw a stereoisomer; (b)...Ch. 15.2 - Prob. 15.3PCh. 15.2 - Prob. 15.4PCh. 15.3 - Prob. 15.5PCh. 15.3 - Prob. 15.6PCh. 15.3 - Prob. 15.7PCh. 15.3 - Prob. 15.8PCh. 15.3 - Prob. 15.9PCh. 15.3 - Prob. 15.10P
Ch. 15.3 - Prob. 15.11PCh. 15.4 - Prob. 15.12PCh. 15.4 - Prob. 15.13PCh. 15.5 - Prob. 15.14PCh. 15.6 - Prob. 15.15PCh. 15.6 - Prob. 15.16PCh. 15.6 - Prob. 15.17PCh. 15.7 - Prob. 15.18PCh. 15.7 - Prob. 15.19PCh. 15.7 - Prob. 15.20PCh. 15.7 - Prob. 15.21PCh. 15.8 - Prob. 15.22PCh. 15.8 - Prob. 15.23PCh. 15.9 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - How are the compounds in each pair related? Are...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Answer each question with a compound of molecular...Ch. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - (a) Define the terms “optically active” and...Ch. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73CPCh. 15 - Prob. 15.74CP
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