Concept explainers
(a)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin formed at the same time
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center. The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(b)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin associated with the condition called jaundice.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(c)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin for which molecular oxygen is used as a reactant.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
(d)
Interpretation: To identify the heme degradation product (1) bilirubin, (2) biliverdin, (3) stercobilin, and (4) urobilin which is bile pigment and has a brownish color.
Concept introduction: Hemoglobin is a heme protein present in the red blood cells. The protein part is called globin and the non-protein part is heme. Heme is the prosthetic group that contains 4 pyrrole groups bonded together and has an iron atom in the center.
The structure of the heme group is:
The first step of degradation of heme involves opening of pyrrole ring with the release of the iron atom and production of biliverdin. The iron atom released becomes part of ferritin protein. Biliverdin produced is converted bilirubin in the spleen. Bilirubin is then transported to the liver where attachment of sugar residues to the propionate side chains of the bilirubin occurs to make it more soluble. Then more solubilized bilirubin is excreted in bile and finally to the small intestine. In the small intestine, it is converted into stercobilin for excretion in feces or urobilin for excretion in urine.
Bile pigments are the colored degradation product of tetrapyrrole carbon arrangement of heme portion of hemoglobin. These are excreted in bile and give characteristic color to urine and feces.
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Chapter 15 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Part C IN H N. Br₂ (2 equiv.) AlBr3 Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and + e (×) H± 12D T EXP. L CONT. דarrow_forward9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3arrow_forwardThere is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forward
- A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forwardProvide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forward
- OA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forward
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