Chapter 14.7, Problem 14.19E

Interpretation Introduction

Interpretation:

$pH$ should be calculated for $0.495M$ aqueous nitrous acid solution.

Concept Introduction:

Acid ionization constant${\text{K}}_{\text{a}}$:

The equilibrium expression for the reaction ${\text{HA}}_{\text{(aq)}}\stackrel{}{\to }{\text{H}}^{\text{+}}{}_{\text{(aq)}}{\text{+A}}^{\text{-}}{}_{\text{(aq)}}$ is given below.

  ${\text{K}}_{\text{a}}\text{=}\frac{{\text{[H}}^{\text{+}}{\text{][A}}^{\text{-}}\text{]}}{\text{[HA]}}$

Where ${\text{K}}_{\text{a}}$ acid ionization is constant, $[{\text{H}}^{\text{+}}\text{]}$ is concentration of hydrogen ion, $[{\text{A}}^{\text{-}}\text{]}$ is concentration of acid anion, $[\text{HA]}$ is concentration of the acid

$pH$ of a solution can be determined by the given formula,

  $\text{pOH}\text{=}-\text{log}\left[H^{+}\right]$