Chapter 14, Problem 80QRT

(a)

Interpretation Introduction

Interpretation:

The Lewis acid and Lewis base in the given reaction has to be determined.

  $H_{2}O\left(l\right)+S{O}_2\left(aq\right)\to H_{2}S{O}_3\left(aq\right)$

Concept introduction:

Lewis acid:

A substance that can accept a pair of electrons to form a new bond is called as Lewis acid.

Lewis base:

A substance that can donate a pair of electrons to form a new bond is called as Lewis base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and Lewis base in the given reaction has to be determined.

  $H_{3}B{O}_3\left(aq\right)+O{H}^{-}\left(aq\right)\to B{\left(OH\right)}_4{}^{-}\left(aq\right)$

Concept introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The Lewis acid and Lewis base in the given reaction has to be determined.

  $C{u}^{2+}\left(aq\right)+4N{H}_3\left(aq\right)\to {\left[Cu{\left(N{H}_3\right)}_4\right]}^{2+}\left(aq\right)$

Concept introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The Lewis acid and Lewis base in the given reaction has to be determined.

  $2C{l}^{-}\left(aq\right)+SnC{l}_2\left(aq\right)\to SnC{l}_4{}^{2-}\left(aq\right)$

Concept introduction:

Refer to part (a).