Explanation Milk of magnesia: The neutralization reaction of milk of magnesia with stomach acid is given below. M g ( O H ) 2 ( s ) + 2 H 3 O + ( a q ) → M g 2 + ( a q ) + 4 H 2 O ( l ) The molar ratio of antacid and the acid is 1 : 2. The moles of stomach acid that is neutralized by 1 g of milk of magnesia can be calculated as given below. 1 g M g ( O H ) 2 × 1 m o l M g ( O H ) 2 58.3196 g M g ( O H ) 2 × 2 m o l H 3 O + 1 m o l M g ( O H ) 2 = 0.03 m o l H 3 O + Calcium carbonate: The neutralization reaction of calcium carbonatewith stomach acid is given below. C a C O 3 ( s ) + 2 H 3 O + ( a q ) → C a 2 + ( a q ) + 3 H 2 O ( l ) + C O 2 ( g ) The molar ratio of antacid and the acid is 1 : 2. The moles of stomach acid that is neutralized by 1 g of calcium carbonate can be calculated as given below. 1 g C a C O 3 × 1 m o l C a C O 3 100.087 g C a C O 3 × 2 m o l H 3 O + 1 m o l C a C O 3 = 0.02 m o l H 3 O + Sodium hydrogen carbonate: The neutralization reaction of sodium hydrogen carbonatewith stomach acid is given below. N a H C O 3 ( s ) + H 3 O + ( a q ) → N a + ( a q ) + 2 H 2 O ( l ) + C O 2 ( g ) The molar ratio of antacid and the acid is 1 : 1. The moles of stomach acid that is neutralized by 1 g of sodium hydrogen carbonatecan be calculated as given below. 1 g N a H C O 3 × 1 m o l N a H C O 3 84.0066 g N a H C O 3 × 1 m o l H 3 O + 1 m o l N a H C O 3 = 0

5th Edition

ISBN: 9781285199047

Author: John W. Moore, Conrad L. Stanitski

Publisher: Cengage Learning

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Chapter 14, Problem 88QRT

Interpretation Introduction

Interpretation:

The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

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Chapter 14, Problem 87QRT

Chapter 14, Problem 89QRT

Chapter 14 Solutions

Chemistry: The Molecular Science

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

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The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

Solution Summary: The author explains the molar ratio of antacid and the acid is 1:2. The moles of stomach acid that is neutralized by 1g of calcium carbonate can be calculated.

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Interpretation: The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.

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Chapter 14 Solutions

Interpretation:

The antacid (milk of magnesia, calcium carbonate, sodium hydrogen carbonate, aluminum hydroxide and dihydroxyaluminum sodium carbonate) which would neutralize the most stomach acid has to be determined.