Explanation The addition of N a O C l to water results into a basic solution. The reaction is given below. O C l − ( a q ) + H 2 O ( l ) ⇌ H O C l ( a q ) + O H − ( a q ) The base ionization constant for the above equation can be written as given below. K b = [ H O C l ] [ O H − ] [ O C l − ] The concentration of H 3 O + can be calculated from the p H as given below. p H = − log [ H 3 O + ] ⇒ [ H 3 O + ] = 10 − p H = 10 − 5.50 = 3.2 × 10 − 6 . A table can be set up as given below. O C l − ( a q ) H O C l ( a q ) O H − ( a q ) I n i t i a l c o n c . ( M ) 0.010 0 1.0 × 10 − 7 C h a n g e i n c o n c . ( M ) − x + x + x E q u i l i b r i u m c o n c

5th Edition

ISBN: 9781285199047

Author: John W. Moore, Conrad L. Stanitski

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 14, Problem 100QRT

Interpretation Introduction

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 99QRT

Chapter 14, Problem 101QRT

Students have asked these similar questions

this is an inorganic chemistry question please answer accordindly!! its just one question with parts till (n) JUST ONE QUESTION with its parts spread out in the form of different images attached 2 IMAGES ATTACHED PLEASE SEE BOTH, please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures, graphs or diagrams, please DRAW DRAW them on a paper and post clearly!! answer the full question with all details as needed EACH PART CLEARLY please or let another expert handle it thanks!! im reposting this please solve all parts and drawit not just word explanations!!

Show work. don't give Ai generated solution

this is an inorganic chemistry question please answer accordindly!! its just one question with parts till (g) JUST ONE QUESTION with its parts spread out in the form of different images attached 2 IMAGES ATTACHED PLEASE SEE ALL, please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures or diagrams, please DRAW DRAW them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!! im reposting this please solve all parts and drawit not just word explanations!!

Chapter 14 Solutions

Chemistry: The Molecular Science

Ch. 14.1 - Identify each molecule or ion as a Brnsted-Lowry...Ch. 14.1 - Using Le Chatelier’s Principle Use Le Chatelier’s...Ch. 14.1 - Prob. 14.3E Ch. 14.1 - Complete the table. Ch. 14.1 - Prob. 14.4E Ch. 14.1 - Prob. 14.5E Ch. 14.2 - Prob. 14.6CE Ch. 14.2 - Prob. 14.7E Ch. 14.3 - Prob. 14.2PSP Ch. 14.3 - Prob. 14.3PSP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The p H of a 0.010 M solution of N a O C l ( K b = 1.5 × 10 − 7 ) has to be calculated.

Solution Summary: The author calculates the pH of a 0.010M solution of NaOClleft.

Concept explainers

Videos

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Want to see the full answer?

Chapter 14 Solutions

The p H of a 0.010 M solution of N a O C l ( K b = 1.5 × 10 − 7 ) has to be calculated.

Solution Summary: The author calculates the pH of a 0.010M solution of NaOClleft.

Concept explainers

Videos

Interpretation: The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The pH of a 0.010 M solution of NaOCl(Kb=1.5×10−7) has to be calculated.