Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group. Concept Introduction: Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses. The number of carbon atoms present in the chain characterize the monosaccharide. They are given below. Carbon chain with three carbon atoms is triose. Carbon chain with four carbon atoms is tetrose. Carbon chain with five carbon atoms is as pentose. Carbon chain with six carbon atoms is as hexose.

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Answer 1

Question

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

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Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)

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Answer 2

Question

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

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Answer 3

Question

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

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Answer 4

Question

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

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Answer 5

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Answer 6

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

Answer 7

Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides. They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal. Monosaccharides that have the carbonyl group at the terminal carbon atom C1 are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom C2 are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide. They are given below.

Carbon chain with three carbon atoms is triose.

Carbon chain with four carbon atoms is tetrose.

Carbon chain with five carbon atoms is as pentose.

Carbon chain with six carbon atoms is as hexose.

Answer 8

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Answer 9

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Answer 10

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Answer 11

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2P Ch. 14.2 - Prob. 14.3P Ch. 14.2 - Prob. 14.4P Ch. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6P Ch. 14.2 - Prob. 14.7P Ch. 14.2 - Prob. 14.8P Ch. 14.2 - Prob. 14.9P Ch. 14.3 - Prob. 14.10P

Solution Summary: The author explains that arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept explainers

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

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Chapter 14 Solutions

Solution Summary: The author explains that arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept explainers

Interpretation: Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group. Concept Introduction: Refer part “a.”.

Interpretation: Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group. Concept Introduction: Refer part “a.”.

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Chapter 14 Solutions

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.