Glycosidic linkage has to be located in given disaccharide. Concept Introduction: Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C − O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms. Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α -glycoside and β -glycoside. In α -glycoside, the bond is oriented down from the carbon C1 while in β -glycoside, the bond is oriented up from the carbon C1 .

Question

Want to see the full answer?

Answer 1

Question

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

The U. S. Environmental Protection Agency (EPA) sets limits on healthful levels of air pollutants. The maximum level that the EPA considers safe for lead air pollution is 1.5 μg/m³ Part A If your lungs were filled with air containing this level of lead, how many lead atoms would be in your lungs? (Assume a total lung volume of 5.40 L.) ΜΕ ΑΣΦ = 2.35 1013 ? atoms ! Check your rounding. Your final answer should be rounded to 2 significant figures in the last step. No credit lost. Try again.

Y= - 0.039 (14.01) + 0.7949

Suppose 1.76 g of magnesium acetate (Mg (CH3CO2)2) are dissolved in 140. mL of water. Find the composition of the resulting electrolyte solution. In particular, list the chemical symbols (including any charge) of each dissolved ion in the table below. List only one ion per row. mEq Then, calculate the concentration of each ion in dwrite the concentration in the second column of each row. Be sure you round your answers to the L correct number of significant digits. ion Add Row mEq L x 5

Answer 2

Question

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Answer 6

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Answer 7

Chapter 14, Problem 14.30UKC

(a)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be located in given disaccharide.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

Answer 10

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Answer 11

(c)

Interpretation Introduction

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2P Ch. 14.2 - Prob. 14.3P Ch. 14.2 - Prob. 14.4P Ch. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6P Ch. 14.2 - Prob. 14.7P Ch. 14.2 - Prob. 14.8P Ch. 14.2 - Prob. 14.9P Ch. 14.3 - Prob. 14.10P

Solution Summary: The author explains the structure of the disaccharide and the numbering of carbon atoms in the ring.

Concept explainers

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).

Want to see the full answer?

Chapter 14 Solutions

Solution Summary: The author explains the structure of the disaccharide and the numbering of carbon atoms in the ring.

Concept explainers

Interpretation: The carbon atoms has to be numbered in both rings of given disaccharide.

Interpretation: Glycosidic linkage has to be classified as α or β in given disaccharide. Concept Introduction: Refer part (a).

Want to see the full answer?

Chapter 14 Solutions

Interpretation:

The carbon atoms has to be numbered in both rings of given disaccharide.

Interpretation:

Glycosidic linkage has to be classified as α or β in given disaccharide.

Concept Introduction:

Refer part (a).