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Practice Problem 14.9
In 1967 R. Breslow (of Columbia University) and co-workers showed that adding
(a) What new
(b) How many
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Organic Chemistry
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- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward(f) Methyl benzene (toluene) reacts with NO₂+ ions in strongly acidic solution, formed by a nitrating mixture of nitric acid and sulfuric acid. NO₂ 0 °C + NO₂* H* CH3 CH3 Name the aromatic product of this reaction (g) Draw the mechanism for this reaction using curly arrows (h) Sketch the ¹H NMR spectrum of phenol. Your answer should indicate the number of distinct ¹H environments (the multiplicity of each resonance peak is not required) (i) Predict, with reasoning, whether you expect the reactivity of phenol towards NO₂+ ions to be greater than the reaction involving methylbenzene. [word limit=50]arrow_forwardAddition of mesitylene to the strongly acidic solvent HF / SbF5 at -45 °C gives a new species which shows a 1H-NMR resonance at δ 4.67 (2H). Draw the structure of this species.arrow_forward
- The azo compound shown below has a λmax value of 410 nm. When treated with hydrogen in the presence of palladium on carbon, the λmax changes significantly. Suggest a reason for this observation and predict whether the λmax value increases or decreases.arrow_forwardAddition of m-xylene to the strongly acidic solvent HF/SbF5 at -45°C gives a new species, which shows 1H-NMR resonances at d 2.88 (3H), 3.00 (3H), 4.67 (2H), 7.93 (1H), 7.83 (1H), and 8.68 (1H). Assign a structure to the species giving this spectrum.arrow_forwardThe enamine prepared from acetone and dimethylamine is shown here in its lowest-energy form. (a) What is the geometry and hybridization of the nitrogen atom? (b) What orbital on nitrogen holds the lone pair of electrons? (c) What is the geometric relationship between the p orbitals of the double bond and the nitrogen orbital that holds the lone pair? Why do you think this geometry represents the minimum energy?arrow_forward
- Furan undergoes electrophilic aromatic substitution more readily than benzene; mild reagents and conditions are sufficient.For example, furan reacts with bromine to give 2-bromofuran.(a) Propose mechanisms for the bromination of furan at the 2-position and at the 3-position. Draw the resonance forms ofeach sigma complex, and compare their stabilities.(b) Explain why furan undergoes bromination (and other electrophilic aromatic substitutions) primarily at the 2-position.O Br O123furan 2-bromofuranarrow_forwardReaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed bytreatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is thestructure of R?arrow_forward(A) what is the hybridization of the nitrogen in each of the following compounds? (B) how does hybridization affect the availability of the lone pair and the basicity of each compound?arrow_forward
- The following sequence of steps converts (R)-2-octanol to (S)-2-octanol. Propose structural formulas for intermediates A and B, specify the configuration of each, and account for the inversion of configuration in this sequence.arrow_forwardWhen 2-bromo-3,3-dimethylbutane is treated with K+ −OC(CH3)3, a single product T having molecular formula C6H12 is formed. When 3,3dimethylbutan-2-ol is treated with H2SO4, the major product U has the same molecular formula. Given the following 1H NMR data, what are the structures of T and U? Explain in detail the splitting patterns observed for the three split signals in T. 1H NMR of T: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, J = 10, 1.7 Hz), 4.93 (doublet of doublets, 1 H, J = 18, 1.7 Hz), and 5.83 (doublet of doublets, 1 H, J = 18, 10 Hz) ppm 1H NMR of U: 1.60 (singlet) ppmarrow_forwardA medicinal chemist at Orgalex Labs, a little known division of a big international pharmaceutical firm, has predicted the major product of the following reaction, an early step in the synthesis of Compound R40 (rumored to be a cure for rhinitis, spontaneous combustion, and bad luck): As Vice-President of Research, it's your job to decide whether the chemist has made a reasonable prediction. If your answer is yes, these could be the major products of the reaction, draw the complete mechanism for the reaction below. If your answer is no, check the box under the drawing area.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning