Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 14, Problem 14PP
Practice Problem 14.14
Explain how
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Combined Spectra
14.46
Identify the C3 H5 Br isomers on the basis of the following information:
(a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49.
(b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2 ); 118.8 (CH2 ); and 134.2 (CH).
(c) Isomer C has two peaks in its 1°C NMR spectrum: 8 12.0 (CH2) and 16.8 (CH). The peak at lower
field is only half as intense as the one at higher field.
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Chemical shift (8, ppm)
Dd.36.
(a) The 'H-NMR spectrum of cyclobutanone shows two signals - signal A at 3.00 ppm and signal B at 1.95 ppm. Give the multiplicity of each signal. cyclobutanone
(b) When cyclobutanone is treated with D20 and NaOD, the only signal observable in the 1H-NMR is a singlet at 2.00 ppm. Explain why this is the case. [Note: Deuterium atoms do not display signals in the TH-NMR spectrum]
Chapter 14 Solutions
Organic Chemistry
Ch. 14 - PRACTICE PROBLEM 14.1 Provide a name for each of...Ch. 14 - Prob. 2PPCh. 14 - Prob. 3PPCh. 14 - Practice Problem 14.4 Apply the polygon-and-circle...Ch. 14 - Practice Problem 14.5 Apply the polygon-and-circle...Ch. 14 - Practice Problem 14.6 1,3,5-Cycloheptatriene is...Ch. 14 - Prob. 7PPCh. 14 - Prob. 8PPCh. 14 - Practice Problem 14.9 In 1967 R. Breslow (of...Ch. 14 - Prob. 10PP
Ch. 14 - Practice Problem 14.11 In addition to a signal...Ch. 14 - PRACTICE PROBLEM 14.12
Azulene has an appreciable...Ch. 14 - Practice Problem 14.13 (a) The -Sh group is...Ch. 14 - Practice Problem 14.14
Explain how NMR...Ch. 14 - PRACTICE PROBLEM 14.15 Four benzenoid compounds,...Ch. 14 - Prob. 16PCh. 14 - Write structural formulas and give acceptable...Ch. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Which of the hydrogen atoms shown below is more...Ch. 14 - 14.22 The rings below are joined by a double bond...Ch. 14 - Prob. 23PCh. 14 - 14.24 (a) In 1960 T. Katz (Columbia University)...Ch. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - 14.27 5-Chloro-1,3-cyclopentadiene (below)...Ch. 14 - Prob. 28PCh. 14 - Furan possesses less aromatic character than...Ch. 14 - 14.30 For each of the pairs below, predict...Ch. 14 - Assign structures to each of the compounds A, B,...Ch. 14 - Prob. 32PCh. 14 - Give a structure for compound F that is consistent...Ch. 14 - Prob. 34PCh. 14 - Prob. 35PCh. 14 - The IR and 1H NMR spectra for compound X(C8H10)...Ch. 14 - Prob. 37PCh. 14 - Prob. 38PCh. 14 - 14.39 Given the following information, predict the...Ch. 14 - Consider these reactions: The intermediate A is a...Ch. 14 - Prob. 41PCh. 14 - Compound E has the spectral features given below....Ch. 14 - Draw all of the molecular orbitals for...Ch. 14 - Prob. 1LGPCh. 14 - Prob. 2LGPCh. 14 - 3. The NMR signals for the aromatic hydrogens of...Ch. 14 - Prob. 4LGPCh. 14 - Prob. 5LGP
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- 13. (a) Compound C undergoes a reaction with SOC12 (or PCls) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.arrow_forward13. (a) Compound C undergoes a reaction with SOC1₂ (or PC15) to yield compound D (Molecular Formula C₁0H₁0OCIBr) which has the following spectral data: Compound D: IR: 1685 cm¹; ¹H NMR: 8 7.84 (d, J = 8 Hz, 2H), 7.60 (d, J=8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹3C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation. (b) Differentiate between the following: i) COSY and NOESY ii) COSY 90 and COSY 45arrow_forward(b) One isomer of dimethoxybenzoic acid has 1H NMR spectrum dµ (ppm) 3.85 (6H, s), 6.63 (1H, t, J 2 Hz), and 7.17 (2H, d, J 2Hz), One isomer of coumalic acid has 'H NMR spectrum dн (ppm) 6.41 (1H, d, J 10 Hz), 7.82 (1H, dd, J 2 Hz, 10 Hz) and 8.51 (1H, d, J 2Hz). In each case, which isomer is represented here? The bonds sticking into the centre of the ring can be to any carbon atom. Note: COOH proton is not indicated in the spectra MeO HO₂C CO2H MeO dimethoxybenzoic acid coumalic acidarrow_forward
- 11. (a) Compound A with molecular formula C10H17NO has the following 'H NMR spectra. Identify the compound and assign & values for each proton. PPMarrow_forward13. (a) Compound C undergoes a reaction with SOC12 (or PC15) to yield compound D (Molecular Formula C₁0H10OCIBr) which has the following spectral data: Compound D: IR: 1685 cm ¹; ¹H NMR: 87.84 (d, J = 8 Hz, 2H), 7.60 (d, J = 8 Hz, 2H), 3.65 (t, J = 7 Hz, 2H), 3.18 (t, J = 7 Hz, 2H), 2.25 (pentet, J = 7 Hz, 2H) ppm; ¹³C NMR: d 28, 36, 45, 128, 130, 133, 137, 197 ppm; EI MS m/z: 200, 198(1:1), 185, 183 (1:1). Identify compound C from the spectral data of compound B and justify your observation.arrow_forward2. Explain in detail how you would distinguish between the following set of constitutional isomers using 13C-NMR. U W Tarrow_forward
- Draw the structure of all constitutional isomers that contain a ketone and have molecular formula C5H10O. Give the IUPAC name for each isomer and state how 13C NMR spectroscopy could be used to distinguish these isomers.arrow_forwardPropose a structure consistent with each set of spectral data: a. C4H8Br2: IR peak at 3000–2850 cm−1; NMR (ppm): 1.87 (singlet, 6 H) 3.86 (singlet, 2 H) b.C3H6Br2: IR peak at 3000–2850 cm−1; NMR (ppm): 2.4 (quintet) 3.5 (triplet) c. C5H10O2: IR peak at 1740 cm−1; NMR (ppm): 1.15 (triplet, 3 H) 2.30 (quartet, 2 H) 1.25 (triplet, 3 H) 4.72 (quartet, 2 H) d.C3H6O: IR peak at 1730 cm−1; NMR (ppm): 1.11 (triplet) 2.46 (multiplet) 9.79 (triplet)arrow_forward10aarrow_forward
- Compound A has a molecular formula C5H11NO and a HNMR spectrum as such: 8.05 (s, 1H), 3.04 (s, 3H), 2.67 (t, 2H), 1.55 (m, 2H), 0.91 (t, 3H). The CNMR shows one peak above 160ppm. When hydrolyzed with H3O+, two compounds are formed B and C after aqueous workup. Draw the structures of A, B, and C.arrow_forwardAn unknown compound has a molecular formula of C3H6O2. Its IR spectrum shows a very strong and broad band at 2980 and a strong sharp peak at 1716 cm-1. It exhibits the following signals in its 1H NMR spectrum (ppm): 1.21 (triplet, 3H), 2.48 (quartet, 2H), 11.7 (singlet, 1H); and the following signals in its 13C NMR spectrum (ppm): 8.9, 27.6, 181.5. Draw the structure of the unknown compound.arrow_forward13.44 Propose structures for compounds that fit the following 'H NMR data: (a) C5H100| 0.95 8 (6 H, doublet, J = 7 Hz) 2.10 8 (3 H, singlet) 2.43 8 (1 H, multiplet) (b) C3H5B1 2.32 8 (3 H, singlet) 5.35 8 (1 H, broad singlet) 5.54 8 (1 H, broad singlet)arrow_forward
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