Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
Question
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Chapter 14, Problem 92AE

(a)

Interpretation Introduction

Interpretation:

Moles of Li2CO3 present in 45.8 mL of solution have to be determined.

Concept Introduction:

Molarity is amount of solute per 1 L of solution. Expression to calculate molarity is as follows:

  Molarity of solution=Moles of soluteVolume (L) of solution

(a)

Expert Solution
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Explanation of Solution

Expression to calculate molarity of Li2CO3 is as follows:

  Molarity of Li2CO3=Moles of Li2CO3Volume (L) of Li2CO3 solution        (1)

Rearrange equation (1) for moles of Li2CO3.

  Moles of Li2CO3=[(Molarity of Li2CO3)(Volume of Li2CO3 solution)]        (2)

Substitute 0.25 M for molarity and 45.8 mL for volume of Li2CO3 solution in equation (2).

  Moles of Li2CO3=(0.25 M)(45.8 mL)(103 L1 mL)=0.01145 mol

Hence, moles of Li2CO3 produced are 0.01145 mol.

(b)

Interpretation Introduction

Interpretation:

Grams of Li2CO3 present in 750 mL of solution have to be determined.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution
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Explanation of Solution

Expression to calculate molarity of Li2CO3 is as follows:

  Molarity of Li2CO3=Moles of Li2CO3Volume (L) of Li2CO3 solution        (1)

Rearrange equation (1) for moles of Li2CO3.

  Moles of Li2CO3=[(Molarity of Li2CO3)(Volume of Li2CO3 solution)]        (2)

Substitute 0.25 M for molarity and 750 mL for volume of Li2CO3 solution in equation (2).

  Moles of Li2CO3=(0.25 M)(750 mL)(103 L1 mL)=0.1875 mol

Expression for mass of Li2CO3 is as follows:

  Mass of Li2CO3=[(Moles of Li2CO3)(Molar mass of Li2CO3)]        (3)

Substitute 0.1875 mol for moles and 73.89 g/mol for molar mass of Li2CO3 in equation (3).

  Mass of Li2CO3=(0.1875 mol)(73.89 g/mol)=13.85 g

Hence, mass of Li2CO3 produced is 13.85 g.

(c)

Interpretation Introduction

Interpretation:

Volume (mL) of Li2CO3 solution that supply 6.0 g of Li2CO3 has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution
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Explanation of Solution

Expression to calculate molarity of Li2CO3 is as follows:

  Molarity of Li2CO3=Moles of Li2CO3Volume (L) of Li2CO3 solution        (1)

Rearrange equation (1) for volume of Li2CO3.

  Volume of Li2CO3 solution=Moles of Li2CO3Molarity of Li2CO3        (3)

Expression for moles of Li2CO3 is as follows:

  Moles of Li2CO3=Mass of Li2CO3Molar mass of Li2CO3        (4)

Substitute 6.0 g for mass and 73.89 g/mol for molar mass of Li2CO3 in equation (4).

  Moles of Li2CO3=6.0 g73.89 g/mol=0.0812 mol

Substitute 0.0812 mol for moles and 0.25 M for molarity of Li2CO3 solution in equation (3).

  Volume of Li2CO3 solution=(0.0812 mol0.25 M)(103 mL1 L)=324.8 mL

Hence, volume of Li2CO3 solution is 324.8 mL.

(d)

Interpretation Introduction

Interpretation:

Mass percent has to be determined if density of solution is 1.22 g/mL.

Concept Introduction:

Mass percent is concentration term used to determine concentration of solution in terms of solute percent in particular mass of solution. Expression for mass percent is as follows:

  Mass percent=(Mass of soluteMass of solution)(100)

(d)

Expert Solution
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Explanation of Solution

Expression for mass percent of Li2CO3 is as follows:

  Mass percent of Li2CO3=(Mass of Li2CO3Mass of solution)(100)        (5)

Expression for mass of solution is as follows:

  Mass of solution=[(Density of solution)(Volume of solution)]        (6)

Substitute 1.22 g/mL for density and 324.8 mL for volume of solution in equation (6).

  Mass of solution=(1.22 g/mL)(324.8 mL)=396.256 g

Substitute 6.0 g for mass of Li2CO3 and 396.256 g for mass of solution in equation (5).

  Mass percent of Li2CO3=(6.0 g396.256 g)(100)=1.51 %

Hence, mass percent of Li2CO3 is 1.51 %.

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Chapter 14 Solutions

Foundations of College Chemistry, Binder Ready Version

Ch. 14.5 - Prob. 14.11PCh. 14.5 - Prob. 14.12PCh. 14 - Prob. 1RQCh. 14 - Prob. 2RQCh. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQCh. 14 - Prob. 6RQCh. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQCh. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 18RQCh. 14 - Prob. 19RQCh. 14 - Prob. 20RQCh. 14 - Prob. 21RQCh. 14 - Prob. 22RQCh. 14 - Prob. 23RQCh. 14 - Prob. 24RQCh. 14 - Prob. 25RQCh. 14 - Prob. 26RQCh. 14 - Prob. 27RQCh. 14 - Prob. 28RQCh. 14 - Prob. 29RQCh. 14 - Prob. 30RQCh. 14 - Prob. 31RQCh. 14 - Prob. 32RQCh. 14 - Prob. 33RQCh. 14 - Prob. 34RQCh. 14 - Prob. 35RQCh. 14 - Prob. 37RQCh. 14 - Prob. 38RQCh. 14 - Prob. 39RQCh. 14 - Prob. 40RQCh. 14 - Prob. 41RQCh. 14 - Prob. 42RQCh. 14 - Prob. 1PECh. 14 - Prob. 2PECh. 14 - Prob. 3PECh. 14 - Prob. 4PECh. 14 - Prob. 5PECh. 14 - Prob. 6PECh. 14 - Prob. 7PECh. 14 - Prob. 8PECh. 14 - Prob. 9PECh. 14 - Prob. 10PECh. 14 - Prob. 11PECh. 14 - Prob. 12PECh. 14 - Prob. 13PECh. 14 - Prob. 14PECh. 14 - Prob. 15PECh. 14 - Prob. 16PECh. 14 - Prob. 17PECh. 14 - Prob. 18PECh. 14 - Prob. 19PECh. 14 - Prob. 20PECh. 14 - Prob. 21PECh. 14 - Prob. 22PECh. 14 - Prob. 23PECh. 14 - Prob. 24PECh. 14 - Prob. 25PECh. 14 - Prob. 26PECh. 14 - Prob. 27PECh. 14 - Prob. 28PECh. 14 - Prob. 29PECh. 14 - Prob. 30PECh. 14 - Prob. 31PECh. 14 - Prob. 32PECh. 14 - Prob. 33PECh. 14 - Prob. 34PECh. 14 - Prob. 35PECh. 14 - Prob. 36PECh. 14 - Prob. 37PECh. 14 - Prob. 38PECh. 14 - Prob. 39PECh. 14 - Prob. 40PECh. 14 - Prob. 41PECh. 14 - Prob. 42PECh. 14 - Prob. 44PECh. 14 - Prob. 45PECh. 14 - Prob. 46PECh. 14 - Prob. 47PECh. 14 - Prob. 48PECh. 14 - Prob. 49PECh. 14 - Prob. 50PECh. 14 - Prob. 51PECh. 14 - Prob. 52PECh. 14 - Prob. 53AECh. 14 - Prob. 54AECh. 14 - Prob. 55AECh. 14 - Prob. 56AECh. 14 - Prob. 57AECh. 14 - Prob. 58AECh. 14 - Prob. 59AECh. 14 - Prob. 60AECh. 14 - Prob. 61AECh. 14 - Prob. 62AECh. 14 - Prob. 63AECh. 14 - Prob. 65AECh. 14 - Prob. 66AECh. 14 - Prob. 67AECh. 14 - Prob. 68AECh. 14 - Prob. 69AECh. 14 - Prob. 70AECh. 14 - Prob. 71AECh. 14 - Prob. 72AECh. 14 - Prob. 73AECh. 14 - Prob. 74AECh. 14 - Prob. 75AECh. 14 - Prob. 76AECh. 14 - Prob. 77AECh. 14 - Prob. 78AECh. 14 - Prob. 79AECh. 14 - Prob. 80AECh. 14 - Prob. 81AECh. 14 - Prob. 82AECh. 14 - Prob. 83AECh. 14 - Prob. 84AECh. 14 - Prob. 85AECh. 14 - Prob. 86AECh. 14 - Prob. 87AECh. 14 - Prob. 88AECh. 14 - Prob. 90AECh. 14 - Prob. 91AECh. 14 - Prob. 92AECh. 14 - Prob. 93AECh. 14 - Prob. 94AECh. 14 - Prob. 95AECh. 14 - Prob. 96AECh. 14 - Prob. 97AECh. 14 - Prob. 98AECh. 14 - Prob. 99CECh. 14 - Prob. 100CECh. 14 - Prob. 102CECh. 14 - Prob. 103CECh. 14 - Prob. 104CECh. 14 - Prob. 105CE
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