Chapter 14, Problem 61AE

Interpretation Introduction

Interpretation:

Molarity of sodium chloride in solution that contains $9.0\text{ g}$ of sodium chloride in one liter of solution has to be determined.

Concept Introduction:

Molarity is amount of solute present in $1\text{ L}$ of solution. Formula to calculate molarity of solution is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$