Chapter 14, Problem 19PE

(a)

Interpretation Introduction

Interpretation:

Moles of solute in $1.5\text{ L}$ of $1.20M{\text{ H}}_2{\text{SO}}_4$ have to be determined.

Concept Introduction:

Molarity is amount of solute per $1\text{ L}$ of solution. Expression to calculate molarity is as follows:

  $\text{Molarity of solution}=\frac{\text{Moles of solute}}{\text{Volume }\left(\text{L}\right)\text{ of solution}}$

(b)

Interpretation Introduction

Interpretation:

Moles of solute in $\text{25}\text{.0 mL}$ of $\text{0}\text{.0015 }M{\text{ BaCl}}_2$ have to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Moles of solute in $\text{125 mL}$ of $\text{0}\text{.35 }M{\text{ K}}_3{\text{PO}}_4$ have to be determined.

Concept Introduction:

Refer to part (a).