Campbell Biology: Custom Edition
18th Edition
ISBN: 9781323717271
Author: Urry, Cain, Wasserman, Minorsky, Reece
Publisher: PEARSON C
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Textbook Question
Chapter 14, Problem 7TYU
The genotype of F1, individuals in a tetrahybrid cross is AaBbCcDd. Assuming lndependent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes?
(a) aabbccdd
(b) AaBbCcDd
(c) AABBCCDD
(d) AaBBccDd
(e) AaBBCCdd
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Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY.
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Chapter 14 Solutions
Campbell Biology: Custom Edition
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Hemochromatosis is an inherited disease caused by...Ch. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Assume that in a series of experiments, plants with round seeds were crossed with plants with wrinkled seeds and the following offspring were obtained: 220 round and 180 wrinkled. (a) What is the most probable genotype of each parent?(b) What genotypic and phenotypic ratios are expected?(c) Based on the information provided in part (b) above, what are the expected (theoretical) numbers of progeny (400 total) of each phenotypic class?arrow_forwardWe have dealt mainly with only two genes, but the sameprinciples hold for more than two genes. Consider thefollowing cross:A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ; D/d ; e/ea. What proportion of progeny will phenotypicallyresemble (1) the first parent, (2) the second parent,(3) either parent, and (4) neither parent?b. What proportion of progeny will be genotypically thesame as (1) the first parent, (2) the second parent,(3) either parent, and (4) neither parent?Assume independent assortment.arrow_forward1) A cross is made between two plants differing in four independently-assorting gene loci, AABBCCDD x aabbccdd, to produce an F, which is then self-fertilized. If the capital letters represent alleles with a completely dominant phenotypic effect, (a) how many different genotypes are possible in the F;? (b) what proportion of the F; will be homozygous dominant for all genes? (c) what proportion of the F; would have an ABCD phenotype? 2) Would your answers to (a), (b), and (c) be different if the initial cross were AAbbCCdd x aaBBccDD?arrow_forward
- Using the forked-line, or branch diagram, method, determine the genotypic and phenotypic ratios of these trihybrid crosses: (a) AaBbCc * AaBBCC, (b) AaBBCc * aaBBCc, and (c) AaBbCc * AaBbCc.arrow_forwardAssume performing only one cross, which produced 274 flies, which consisted of 193 wild-type flies and 81 white-eyed flies. (a) Based upon this information, what is the most likely genotype of the female parent? (b) How to confirm the above answer with only the result from this one cross?arrow_forward1) S-Tu-U 2) S-U-Tu 3) Tu-S-U 4) U-S-Tuarrow_forward
- Based on the information you discovered in the previous problem, answer the following:a. A female fruit fly with genotype Tt nn is mated toa male of genotype Tt Nn. What is the probabilitythat any one of their offspring will have normalphenotypes for both characters?b. What phenotypes would you expect among the offspring of this cross? If you obtained 200 progeny, howmany of each phenotypic class would you expect?arrow_forwardIn garden peas, yellow seeds (Y)(Y) are dominant to green seeds (y)(y), and inflated pods (I)(I) are dominant to constricted pods (i)(i). Suppose you have crossed YYIIYYII parents with yyiiyyii parents. What would be all the genotype(s) of gametes produced by F1F1 individuals?arrow_forwardThe expected ratio of phenotypes among the progeny of a test cross is 1:1:1:1. Out of 200 total resulting progeny, 48 occur in one of the four phenotypic classes. Given this information, which of the following must also be true? a)At least one additional cell must also contain a count of 48. b)The progeny of this cross do not conform to a 1:1:1:1ratio. c)The value of observed - expected for this cell = -2. d)Since 48 is so close to the expected value, there is no need to calculate chi square before drawing a conclusion about the ratio.arrow_forward
- In Figure 4-6, why does the diagram not show meiosesin which two crossovers occur between the same twochromatids (such as the two inner ones)?arrow_forwardIn sesame plants, the one-pod condition (P) is dominant to the three-pod condition (p), and normal leaf (L) is dominant to wrinkled leaf (l). Pod type and leaf type are inherited independently. Determine the genotypes for the two parents for all possible matings producing the following offspring: 318 one-pod, normal leaf and 98 one-pod, wrinkled leaf. show your solution using punnet squarearrow_forwardIn onion, male sterility is produced when the nuclear genotype is aa and the mitochondrial gene S (sterile) are present. Any other combination of nuclear genotype and mitochondrial gene (including gene F for fertile) will result in a male fertile plant. Give the genotypic ratio and the phenotypic ratio or the percentage of male sterile and male fertile offspring that will be produced in the following crosses. 1. Aa + S male x aa + F female 2. Reciprocal cross of number 1. (Note that when we do reciprocal cross, we interchange/swap the genotypes of the parents (if there is a nuclear gene involved, you interchange the nuclear genotype as well). 3. Aa + S female x Aa + F male 4. Reciprocal cross of number 3.arrow_forward
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