Campbell Biology: Custom Edition
18th Edition
ISBN: 9781323717271
Author: Urry, Cain, Wasserman, Minorsky, Reece
Publisher: PEARSON C
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Chapter 14.3, Problem 3CC
WHAT IF? Ø A rooster with gray feathers and a hen of the same phenotype produce 15 gray, 6 black, and 8 white chicks. What is the simplest explanation for the inheritance of these colors in chickens? What
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For number 15-24. In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that
wooly hair (W) is dominant over non-wooly hair (w). Cross a heterozygous parent (SsWw) with a
heterozygous parent (Ssww) Give genotypic and phenotypic ratios of offspring.
15-18. What is the probability of producing spotted skin with non-wooly hair?
8/16
4/16
3/16
6/16
8/16
A.
B.
C.
D.
E.
19-21. What is the probability of producing non-spotted skin with non-wooly hair?
A
2/16
B.
4/16
C.
1/16
D.
6/16
22-24. What is the probability of producing non-spotted skin with wooly hair?
A 3/16
В. 4/16
с. 1/16
D. 9/16
E. 8/16
Chapter 14 Solutions
Campbell Biology: Custom Edition
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Hemochromatosis is an inherited disease caused by...Ch. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Crossing Pea Plants: Mendels Study of Single Traits Stem length in pea plants is controlled by a single gene. Consider the cross of a true-breeding long-stemmed variety to a true-breeding short-stemmed variety in which long stems are completely dominant. a. If 120 F1 plants are examined, how many plants are expected to be long stemmed? Short stemmed? b. Assign genotypes to both P1 varieties and to all phenotypes listed in (a). c. A long-stemmed F1 plant is self-crossed. Of 300 F2 plants, how many should be long stemmed? Short stemmed? d. For the F2 plants mentioned in (c), what is the expected genotypic ratio?arrow_forwardEXAMPLE PROBLEM Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents? Dominance and recessive describe which of two possible phenotypes are exhibited when two different alleles occur in the same individual.arrow_forwardO Hydrolyze lactose into glucose and galactose for cellular metabolism A red-flower plant crossed with a white-flower plant of the same species, produced F1 with all pink flowers. Self-pollination of the F1 plant produced F2 generation with 39 red-flower plants, 83 pink-flower plants and 40 white-flower plants. What does this experiment demonstrate? * Codominanoce O Incomplete dominance O Polygenic inheritance Multiple alleles In organism A, blue skin colour is dominant over yellow. If, heterozygous blue skinarrow_forward
- In Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. What are the resulting phenotypes? Don’t forget to take epistasis into account!arrow_forwardO e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook Airarrow_forwardIn jellyfish, let's say that long tentacles are produced by a sex-influenced allele that is dominant in males and recessive in females. Let B1 = long and B2 = short. Which of the following correctly diagrams a cross between a female with long tentacles and a male with short tentacles? O B1B1XX X B1B2XY O B1B2 XX X B1B2 XY O females with long tentacles do not exist, so this cross is impossible O B1B1 XX X B2B2 XY O X(B1) X(B2) x X(B2) Yarrow_forward
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