Chapter 14, Problem 45A

To determine

The spring compressed of it supports the car’s weight.

Answer to Problem 45A

  $0.12\text{m}$

Explanation of Solution

Given:Spring constant: $25000\text{N/m}$

Restoring force: $\frac{1}{4}\left(12000\right)\text{N}$

Formula Used:

The formula required to find compressed spring:

  $\begin{array}{l}F=kx\\ x=\frac{F}{k}\end{array}$

Where,

  $x$ : Compressed spring.

  $F$ : restoring force.

  $k$ : Spring constant

Calculation:

Put the given values,

  $\begin{array}{l}x=\frac{F}{k}\\ x=\frac{\left(\frac{1}{4}\right)12000}{25000}\\ x=0.12\text{m}\end{array}$

Conclusion:The spring compressed by $x=0.12\text{m}$ .