Chapter 14.1, Problem 5PP

To determine

The period of a pendulumon Earth.

Answer to Problem 5PP

  $2.0s$

Explanation of Solution

Given information:

Length of the pendulum, $l=1.0\text{m}$

Formula used:

The period of pendulum is:

  $T=2\pi \sqrt{\frac{l}{g}}$

Here, l is the length of the pendulum and g is the acceleration due to gravity.

Calculation:

  $g$

  $=9.8m/s²$ (the standard value of $g$ )

Now, substitute the values and solve:

  $T$

  $=2\pi \sqrt{\frac{1.0m}{9.8m/s²}}$

  $T$

  $=2.0s$

Conclusion:

Thus, the period of the pendulum on Earth is $2.0s$ .