Chapter 14.2, Problem 21PP

To determine

The speed of the wave of coiled spring toy.

Answer to Problem 21PP

  $12.0m/s$

Explanation of Solution

Given info:

Distance between successive compressions (wavelength), $\lambda =0.600m$

Frequency, $f$

  $=20.0Hz$

Formula used:

The relationship of speed of the sound, frequency and wavelength:

  $v=f\lambda$

Where,

  $v$ is the sound speed, $f$ is its frequency and $\lambda$ is its wavelength.

Calculation:

  $v=f\lambda$

Substitute the values

  $\begin{array}{l}v=\left(20.0Hz\right)\left(0.600m\right)\\ v=12.0m/s\end{array}$

Conclusion:

Therefore, the speed of the wave of coiled spring toy is $12.0m/s$ .