Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 14, Problem 25RQ
Summary Introduction
To review:
The reason for the development of pernicious anemia in vegans if they consume antibiotic.
Introduction:
Vegans are individuals who do not eat meat and meat products as well as milk and dairy products. The inability of the body to produce healthy red blood cells (RBCs) because of vitamin B12 deficiency is pernicious anemia. It may also be caused because of the body’s inability to absorb the vitamin. The common symptoms include headache, weakness, chest pain, weight loss, spasticity, memory loss, and peripheral neuropathy.
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Students have asked these similar questions
One of the codons for Alanine is 5’GCA3’. Which of the following tRNA
sequences base pairs with this codon?
5’GCA3’
5’ACG3’
5’UGC3’
5’CGU3’
Select Any that Apply
Which of the following protein factors hydrolyses GTP?
IF-1
IF-2
IF-3
EF-Tu
EF-G
EF-Ts
RF1
RF2
Question 4
Question 4
1 Point
What is a mRNA that codes for a single protein called?
Blank 1
5.) Draw Gly-Phe-Lys-Lys as it would appear at pH 1
Explain your answer thoroughly.
3. Identify carbons 3 and 5 in the monosaccharides below
H
H
H
H
OH
0
H
0
CH₂OH
H
CH₂OH
OH
H
0
H
CH₂OH
о
H
H
H
OH
OH
H
OH
H
OH
OH
OH
H
OH
OH
H
OH
OH
OH
CH₂OH
1
H
H
H
H
Chapter 14 Solutions
Biochemistry: The Molecular Basis of Life
Ch. 14 - Prob. 1QCh. 14 - Prob. 2QCh. 14 - Prob. 3QCh. 14 - Prob. 4QCh. 14 - Prob. 5QCh. 14 - Prob. 1RQCh. 14 - Prob. 2RQCh. 14 - Prob. 3RQCh. 14 - Prob. 4RQCh. 14 - Prob. 5RQ
Ch. 14 - Prob. 6RQCh. 14 - Prob. 7RQCh. 14 - Prob. 8RQCh. 14 - Prob. 9RQCh. 14 - Prob. 10RQCh. 14 - Prob. 11RQCh. 14 - Prob. 12RQCh. 14 - Prob. 13RQCh. 14 - Prob. 14RQCh. 14 - Prob. 15RQCh. 14 - Prob. 16RQCh. 14 - Prob. 17RQCh. 14 - Prob. 18RQCh. 14 - Prob. 19RQCh. 14 - Prob. 20RQCh. 14 - Prob. 21RQCh. 14 - Prob. 22RQCh. 14 - Prob. 23RQCh. 14 - Prob. 24RQCh. 14 - Prob. 25RQCh. 14 - Prob. 26RQCh. 14 - Prob. 27RQCh. 14 - Prob. 28RQCh. 14 - Prob. 29RQCh. 14 - Prob. 30RQCh. 14 - Prob. 31RQCh. 14 - Prob. 32RQCh. 14 - Prob. 33RQCh. 14 - Prob. 34RQCh. 14 - Prob. 35RQCh. 14 - Prob. 36RQCh. 14 - Prob. 37FBCh. 14 - Prob. 38FBCh. 14 - Prob. 39FBCh. 14 - Prob. 40FBCh. 14 - Prob. 41FBCh. 14 - Prob. 42FBCh. 14 - Prob. 43FBCh. 14 - Prob. 44FBCh. 14 - Prob. 45FBCh. 14 - Prob. 46FBCh. 14 - Prob. 47SACh. 14 - Prob. 48SACh. 14 - Prob. 49SACh. 14 - Prob. 50SACh. 14 - Prob. 51SACh. 14 - Prob. 52TQCh. 14 - Prob. 53TQCh. 14 - Prob. 54TQCh. 14 - Prob. 55TQCh. 14 - Prob. 56TQCh. 14 - Prob. 57TQCh. 14 - Prob. 58TQCh. 14 - Prob. 59TQCh. 14 - Prob. 60TQCh. 14 - Prob. 61TQCh. 14 - Prob. 63TQ
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- 3. Identify carbons 3 and 5 in the monosaccharides below H H H H OH 0 H 0 CH₂OH H CH₂OH OH H 0 H CH₂OH о H H H OH OH H OH H OH OH OH H OH OH H OH OH OH CH₂OH 1 H H H Harrow_forwardApply your knowledge Why are monosaccharides highly soluble in water? Why do monosaccharides have high boiling and melting points? Identify carbons 3 and 5 in the monosaccharides below 9 Reducing & non - reducing sugars ( Learning goal 5) A classification that helps differentiate monosaccharides Reducing sugars Also known as aldoses. E. g. glucose Changes Benedicts solution from ) blue to redarrow_forwardBook problem 28-22: Human and horse insulin both have two polypeptide chains, with one chain containing 21 amino acids and the other containing 30 amino acids. They differ in primary structure at two places. At position 9 in one chain, human insulin has Ser and horse insulin has Gly; at position 30 in the other chain, human insulin has Thr and horse insulin has Ala. How must the DNA for the two insulins differ? Book problem 28-24: The codon UAA stops protein synthesis. Why does the sequence UAA in the following stretch of mRNA not cause any problems? Provide a 1-2 sentence response. -GCA-UUC-GAG-GUA-ACG-CCC- For what amino acids do the following ribonucleotide triplets code?arrow_forward
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- Draw the structure of 2, 2-diiodobutane and convert this achiral compound to chiral compound by changing ONLY 1 atom in the structure. Name the new compound.arrow_forwardIdentify the chiral carbon atoms in each structure. If no chiral carbon atoms are present write: "None present". a) 1 2 3 4 LO 6 b) 8 10 7 CI 9 7 6 5 4 13 CI 2 1arrow_forwardHOCH2 HOCH2 OH OH OCH3 OCH 3 OH OH 1) Is this structure a monosaccharide or disaccharide or trisaccharide? 2) What is the molecular formula of this structure? 3) Is this compound soluble in water? 4) What type of sugars are present (D or L)? Explainarrow_forward
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