Disaccharide structure has to be drawn that will be formed by 1 → 4 − β − glycosidic linkage of galactose. Concept Introduction: Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C − O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms. Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α -glycoside and β -glycoside. In α -glycoside, the bond is oriented down from the carbon C1 while in β -glycoside, the bond is oriented up from the carbon C1 .

Question

Want to see the full answer?

Answer 1

Question

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Question

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Answer 6

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Answer 7

Chapter 14, Problem 14.65AP

Interpretation Introduction

Interpretation:

Disaccharide structure has to be drawn that will be formed by 1→4−β− glycosidic linkage of galactose.

Concept Introduction:

Carbohydrates that are composed of two monosaccharide units are known as disaccharides. This is formed when one hydroxyl group of one monosaccharide reacts with a hydroxyl group of another monosaccharide. The bond formed between the two monosaccharide units is C−O bond and this linkage is known as glycosidic linkage. Carbon atom that is present in the glycosidic linkage is bonded to two oxygen atoms.

Depending on the orientation of the glycosidic linkage, the glycoside bond can be of two types. They are α-glycoside and β-glycoside. In α-glycoside, the bond is oriented down from the carbon C1 while in β-glycoside, the bond is oriented up from the carbon C1.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2P Ch. 14.2 - Prob. 14.3P Ch. 14.2 - Prob. 14.4P Ch. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6P Ch. 14.2 - Prob. 14.7P Ch. 14.2 - Prob. 14.8P Ch. 14.2 - Prob. 14.9P Ch. 14.3 - Prob. 14.10P

Solution Summary: The author explains that disaccharides are formed when one hydroxyl group reacts with another hydride. The glycoside bond is formed between the first carbon of one galactose unit and the fourth carbon atom

Concept explainers

Want to see the full answer?

Chapter 14 Solutions