Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
2nd Edition
ISBN: 9780077633707
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
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Question
Chapter 14.2, Problem 14.9P
(a)
Interpretation Introduction
Interpretation:
Fischer projection for D-galactose has to be drawn.
Concept Introduction:
Fischer projection formula simply uses cross for representing tetrahedral carbon atom. The carbon atom that is present in the intersection point in cross. The horizontal bonds means they are coming forward and they are present on wedge bond. The vertical bonds means they are pointing away and they are present on dashed lines.
(b)
Interpretation Introduction
Interpretation:
Fischer projection for the enantiomer of D-galactose has to be drawn.
Concept Introduction:
Enantiomers are two stereoisomers of a compound that rotate the plane polarized light exactly opposite. The configuration present in the enantiomers will be exactly opposite to each other.
Fischer projection formula simply uses cross for representing tetrahedral carbon atom. The carbon atom that is present in the intersection point in cross. The horizontal bonds means they are coming forward and they are present on wedge bond. The vertical bonds means they are pointing away and they are present on dashed lines.
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Students have asked these similar questions
(a) Draw the condensed structural formula, and give the name for the dipeptide Pro-Asn.
(b) Draw the disaccharide formed by the following two monosaccharide via 1,4-linkage. In your disaccharide
structure, circle and label the anomeric carbon and indicate whether you have an alpha (a) or a beta (B)
anomer.
CH2OH
CH₂OH
ОН
ОН
ОН
ОН,
ОН
ОН
ОН
ОН
Monosaccharides can be categorized in terms of thenumber of carbon atoms (pentoses have five carbons andhexoses have six carbons) and according to whether theycontain an aldehyde (aldo- prefix, as in aldopentose) orketone group (keto- prefix, as in ketopentose). Classify glucoseand fructose in this way.
A) Define "reducing sugar." (b) Sucrose is a disaccharide composed of glucose and fructose (Glc(1 → 2)Fru). Explain why sucrose is not a reducing sugar, even though both glucose and fructose are.
Chapter 14 Solutions
Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2PCh. 14.2 - Prob. 14.3PCh. 14.2 - Prob. 14.4PCh. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6PCh. 14.2 - Prob. 14.7PCh. 14.2 - Prob. 14.8PCh. 14.2 - Prob. 14.9PCh. 14.3 - Prob. 14.10P
Ch. 14.3 - Prob. 14.11PCh. 14.4 - Prob. 14.12PCh. 14.4 - Prob. 14.13PCh. 14.4 - Prob. 14.14PCh. 14.4 - Prob. 14.15PCh. 14.5 - Prob. 14.16PCh. 14.5 - Prob. 14.17PCh. 14.5 - Prob. 14.18PCh. 14.5 - Prob. 14.19PCh. 14.6 - Prob. 14.20PCh. 14 - Prob. 14.21UKCCh. 14 - Prob. 14.22UKCCh. 14 - Prob. 14.23UKCCh. 14 - Prob. 14.24UKCCh. 14 - Prob. 14.25UKCCh. 14 - Prob. 14.26UKCCh. 14 - Prob. 14.27UKCCh. 14 - Prob. 14.28UKCCh. 14 - Prob. 14.29UKCCh. 14 - Prob. 14.30UKCCh. 14 - Prob. 14.31APCh. 14 - Prob. 14.32APCh. 14 - Prob. 14.33APCh. 14 - Prob. 14.34APCh. 14 - Prob. 14.35APCh. 14 - Prob. 14.36APCh. 14 - Prob. 14.37APCh. 14 - Prob. 14.38APCh. 14 - Prob. 14.39APCh. 14 - Prob. 14.40APCh. 14 - Prob. 14.41APCh. 14 - Prob. 14.42APCh. 14 - Prob. 14.43APCh. 14 - Prob. 14.44APCh. 14 - Prob. 14.45APCh. 14 - Prob. 14.46APCh. 14 - Prob. 14.47APCh. 14 - Prob. 14.48APCh. 14 - Prob. 14.49APCh. 14 - Prob. 14.50APCh. 14 - Prob. 14.51APCh. 14 - Prob. 14.52APCh. 14 - Prob. 14.53APCh. 14 - Prob. 14.54APCh. 14 - Prob. 14.55APCh. 14 - Prob. 14.56APCh. 14 - Prob. 14.57APCh. 14 - Prob. 14.58APCh. 14 - Prob. 14.59APCh. 14 - Prob. 14.60APCh. 14 - Prob. 14.61APCh. 14 - Prob. 14.62APCh. 14 - Prob. 14.63APCh. 14 - Prob. 14.64APCh. 14 - Prob. 14.65APCh. 14 - Prob. 14.66APCh. 14 - Prob. 14.67APCh. 14 - Prob. 14.68APCh. 14 - Prob. 14.69APCh. 14 - Prob. 14.70APCh. 14 - Prob. 14.71APCh. 14 - Prob. 14.72APCh. 14 - Prob. 14.73CPCh. 14 - Prob. 14.74CP
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