Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
2nd Edition
ISBN: 9780077633707
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
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Chapter 14, Problem 14.47AP
Interpretation Introduction
Interpretation:
Reason has to be given for not using D, L labels for ketotriose.
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Identify the type of glycosidic bond in the following disaccharide.
CH,OH
H
H
ОН Н
CH2
H
H
H
ОН Н
HO
ОН
H.
ОН
HO
H
H
OH
O B-1,4-glycosidic bond
O a-1,4-glycosidic bond
O B-1,6-glycosidic bond
O a-1,6-glycosidic bond
What is a ketopentose?
Chapter 14 Solutions
Connect 1-Semester Online Access for Principles of General, Organic & Biochemistry
Ch. 14.1 - Draw a Lewis structure for glucose that clearly...Ch. 14.2 - Prob. 14.2PCh. 14.2 - Prob. 14.3PCh. 14.2 - Prob. 14.4PCh. 14.2 - Rank the following compounds in order of...Ch. 14.2 - Prob. 14.6PCh. 14.2 - Prob. 14.7PCh. 14.2 - Prob. 14.8PCh. 14.2 - Prob. 14.9PCh. 14.3 - Prob. 14.10P
Ch. 14.3 - Prob. 14.11PCh. 14.4 - Prob. 14.12PCh. 14.4 - Prob. 14.13PCh. 14.4 - Prob. 14.14PCh. 14.4 - Prob. 14.15PCh. 14.5 - Prob. 14.16PCh. 14.5 - Prob. 14.17PCh. 14.5 - Prob. 14.18PCh. 14.5 - Prob. 14.19PCh. 14.6 - Prob. 14.20PCh. 14 - Prob. 14.21UKCCh. 14 - Prob. 14.22UKCCh. 14 - Prob. 14.23UKCCh. 14 - Prob. 14.24UKCCh. 14 - Prob. 14.25UKCCh. 14 - Prob. 14.26UKCCh. 14 - Prob. 14.27UKCCh. 14 - Prob. 14.28UKCCh. 14 - Prob. 14.29UKCCh. 14 - Prob. 14.30UKCCh. 14 - Prob. 14.31APCh. 14 - Prob. 14.32APCh. 14 - Prob. 14.33APCh. 14 - Prob. 14.34APCh. 14 - Prob. 14.35APCh. 14 - Prob. 14.36APCh. 14 - Prob. 14.37APCh. 14 - Prob. 14.38APCh. 14 - Prob. 14.39APCh. 14 - Prob. 14.40APCh. 14 - Prob. 14.41APCh. 14 - Prob. 14.42APCh. 14 - Prob. 14.43APCh. 14 - Prob. 14.44APCh. 14 - Prob. 14.45APCh. 14 - Prob. 14.46APCh. 14 - Prob. 14.47APCh. 14 - Prob. 14.48APCh. 14 - Prob. 14.49APCh. 14 - Prob. 14.50APCh. 14 - Prob. 14.51APCh. 14 - Prob. 14.52APCh. 14 - Prob. 14.53APCh. 14 - Prob. 14.54APCh. 14 - Prob. 14.55APCh. 14 - Prob. 14.56APCh. 14 - Prob. 14.57APCh. 14 - Prob. 14.58APCh. 14 - Prob. 14.59APCh. 14 - Prob. 14.60APCh. 14 - Prob. 14.61APCh. 14 - Prob. 14.62APCh. 14 - Prob. 14.63APCh. 14 - Prob. 14.64APCh. 14 - Prob. 14.65APCh. 14 - Prob. 14.66APCh. 14 - Prob. 14.67APCh. 14 - Prob. 14.68APCh. 14 - Prob. 14.69APCh. 14 - Prob. 14.70APCh. 14 - Prob. 14.71APCh. 14 - Prob. 14.72APCh. 14 - Prob. 14.73CPCh. 14 - Prob. 14.74CP
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- 5. Use B-D-glucose (below) to draw the disaccharides that are connected by 1-3 and 2-4 linkages. JOH НО HO OH B-D-glucose OH OH OH Ex OH НО CHarrow_forwardThe number of glycosidic bond in the structure is 5 4 1 2 3arrow_forward7. Draw the Haworth structure for the following monosaccharides a. H НО H c=0 H + но - н 3 4 Н 5 - ОН - OH 애 CH₂OH 6 D-Mannose b. H 0 = с H - C - OH HO-C - H H - C - OH H - C - ОН CH₂OH Glucosearrow_forward
- in the following molecule the glycosidic bond is circled. CH2OH CH2OH H CH2OH OH HO H H НО H. ОН ÓH True Falsearrow_forwardIdentify if the statement is TRUE or FALSE. If false, write the word/s that make(s) the statement incorrect. 1. The N in fertilizers are in the form NH4+ and NO3-2. Assimilated NH4+ reacts with α-ketoglutarate to form Gln.arrow_forwardDraw the left and right saccharide formed when the disaccharide is hydrolyzed?arrow_forward
- Amygdalin is a toxic component in the pits of bitter almonds, peaches, and apricots. Q.) Name the two monosaccharide units in amygdalin and describe the glycosidic bond by which they are joined.arrow_forward• Question 4: (a) Label the four stereogenic centers in sorbitol as R or S. (b) How are sorbitol and A related? (c) How are sorbitol and B related? НО ННО Н НО H OH HO H sorbitol OH НО НО Н НОн H OHH OH A OH HO H OH H OH HO H H OH B OHarrow_forwardLabel each reaction as an oxidation or reduction, and give the reagent, NAD + or NADH, that would be used to carry out the reaction.arrow_forward
- Explain what a β-1,4-glycosidic bond is made up of? (ie. Breakdown how a bond is considered a β-1,4-glycosidic bond?arrow_forwardFor each monosaccharide: [1] determine all acetal and hemiacetal carbons; [2] select the anomeric carbon; [3] designate the compound as an a or ß anomer, 6 CH2OH 5. H H CH2OH O 1CH2OH OH OH H a. 4 b. H H 12 OH ÓH Но H ÓH ÓH a. Carbon 1 is the hemiacetal carbon. Carbon 2 is the v acetal carbon. Carbon 4 is the v anomeric carbon. The compound is B b. Carbon 2 is the hemiacetal carbon. There is not an v acetal carbon. Carbon 4 is the v anomeric carbon. The compound is a v I-arrow_forwardWhat type of glycosidic bond is shown here? CH2OH H. H. H. OH H. OH CH2 H. HO H. H. HO H. HO. OH H. HO. a(1→6) 工 エarrow_forward
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