General, Organic, and Biological Chemistry Seventh Edition
General, Organic, and Biological Chemistry Seventh Edition
7th Edition
ISBN: 9781305767867
Author: H. Stephan Stoker
Publisher: Cengage Learning
Question
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Chapter 14, Problem 14.25EP

(a)

Interpretation Introduction

Interpretation:

The given alcohol structures denotes a cis- or trans- isomer has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Cycloalkanes can also exhibit stereoisomerism.  The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism.  Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space.  Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms.  Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.

(b)

Interpretation Introduction

Interpretation:

The given alcohol structures denotes a cis- or trans- isomer has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Cycloalkanes can also exhibit stereoisomerism.  The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism.  Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space.  Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms.  Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.

(c)

Interpretation Introduction

Interpretation:

The given alcohol structures denotes a cis- or trans- isomer has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Cycloalkanes can also exhibit stereoisomerism.  The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism.  Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space.  Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms.  Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.

(d)

Interpretation Introduction

Interpretation:

The given alcohol structures denotes a cis- or trans- isomer has to be indicated.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it.  There will not be any free rotation of the double bond in alkene.  Hence, cis‑trans isomerism is possible.  The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Cycloalkanes can also exhibit stereoisomerism.  The difference between constitutional isomerism and stereoisomerism is that, the result of difference in connectivity of carbon atoms is known as constitutional isomerism and the result of differences in configuration is known as stereoisomerism.  Stereoisomers are compounds that possess same molecular formula and connectivity of atoms but different orientations of atoms in space.  Cis isomers are the one where the two substituted groups on different carbon atom are present above or below the plane or the ring of carbon atoms.  Trans isomers are the one where the two substituted groups on different carbon atom are present one above and one below the plane or the ring of carbon atoms.

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Chapter 14 Solutions

General, Organic, and Biological Chemistry Seventh Edition

Ch. 14.4 - Prob. 2QQCh. 14.4 - Prob. 3QQCh. 14.5 - Prob. 1QQCh. 14.5 - Prob. 2QQCh. 14.5 - Prob. 3QQCh. 14.5 - Prob. 4QQCh. 14.6 - Prob. 1QQCh. 14.6 - Prob. 2QQCh. 14.6 - Prob. 3QQCh. 14.7 - Prob. 1QQCh. 14.7 - Prob. 2QQCh. 14.8 - Prob. 1QQCh. 14.8 - Prob. 2QQCh. 14.9 - Prob. 1QQCh. 14.9 - Prob. 2QQCh. 14.9 - Prob. 3QQCh. 14.9 - Prob. 4QQCh. 14.9 - Prob. 5QQCh. 14.9 - Prob. 6QQCh. 14.10 - Prob. 1QQCh. 14.10 - Prob. 2QQCh. 14.11 - Prob. 1QQCh. 14.11 - Prob. 2QQCh. 14.11 - Prob. 3QQCh. 14.12 - Prob. 1QQCh. 14.12 - Prob. 2QQCh. 14.13 - Prob. 1QQCh. 14.13 - Prob. 2QQCh. 14.13 - Prob. 3QQCh. 14.14 - Prob. 1QQCh. 14.14 - Prob. 2QQCh. 14.14 - Prob. 3QQCh. 14.15 - Prob. 1QQCh. 14.15 - Prob. 2QQCh. 14.15 - Prob. 3QQCh. 14.15 - Prob. 4QQCh. 14.16 - Prob. 1QQCh. 14.16 - Prob. 2QQCh. 14.17 - Prob. 1QQCh. 14.17 - Prob. 2QQCh. 14.17 - Prob. 3QQCh. 14.18 - Prob. 1QQCh. 14.18 - Prob. 2QQCh. 14.18 - Prob. 3QQCh. 14.19 - Prob. 1QQCh. 14.19 - Prob. 2QQCh. 14.20 - Prob. 1QQCh. 14.20 - Prob. 2QQCh. 14.20 - Prob. 3QQCh. 14.20 - Prob. 4QQCh. 14.20 - Prob. 5QQCh. 14.21 - Prob. 1QQCh. 14.21 - Prob. 2QQCh. 14.21 - Prob. 3QQCh. 14.21 - Prob. 4QQCh. 14.21 - Prob. 5QQCh. 14 - Prob. 14.1EPCh. 14 - Prob. 14.2EPCh. 14 - Prob. 14.3EPCh. 14 - Prob. 14.4EPCh. 14 - Prob. 14.5EPCh. 14 - Prob. 14.6EPCh. 14 - Prob. 14.7EPCh. 14 - Prob. 14.8EPCh. 14 - Prob. 14.9EPCh. 14 - Prob. 14.10EPCh. 14 - Write a condensed structural formula for each of...Ch. 14 - Write a condensed structural formula for each of...Ch. 14 - Prob. 14.13EPCh. 14 - Prob. 14.14EPCh. 14 - Prob. 14.15EPCh. 14 - Prob. 14.16EPCh. 14 - Prob. 14.17EPCh. 14 - Prob. 14.18EPCh. 14 - Each of the following alcohols is named...Ch. 14 - Prob. 14.20EPCh. 14 - Prob. 14.21EPCh. 14 - Prob. 14.22EPCh. 14 - Prob. 14.23EPCh. 14 - Prob. 14.24EPCh. 14 - Prob. 14.25EPCh. 14 - Prob. 14.26EPCh. 14 - Prob. 14.27EPCh. 14 - Prob. 14.28EPCh. 14 - Prob. 14.29EPCh. 14 - Prob. 14.30EPCh. 14 - Prob. 14.31EPCh. 14 - Prob. 14.32EPCh. 14 - Prob. 14.33EPCh. 14 - Prob. 14.34EPCh. 14 - Explain why the boiling points of alcohols are...Ch. 14 - Explain why the water solubilities of alcohols are...Ch. 14 - Prob. 14.37EPCh. 14 - Prob. 14.38EPCh. 14 - Prob. 14.39EPCh. 14 - Which member of each of the following pairs of...Ch. 14 - Determine the maximum number of hydrogen bonds...Ch. 14 - Determine the maximum number of hydrogen bonds...Ch. 14 - Prob. 14.43EPCh. 14 - Prob. 14.44EPCh. 14 - Prob. 14.45EPCh. 14 - Prob. 14.46EPCh. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Classify each of the following alcohols as a...Ch. 14 - Prob. 14.51EPCh. 14 - Prob. 14.52EPCh. 14 - Prob. 14.53EPCh. 14 - Prob. 14.54EPCh. 14 - Prob. 14.55EPCh. 14 - Prob. 14.56EPCh. 14 - Prob. 14.57EPCh. 14 - Prob. 14.58EPCh. 14 - Prob. 14.59EPCh. 14 - Prob. 14.60EPCh. 14 - The alcohol 2,2-dimethyl-1-butanol cannot be...Ch. 14 - Prob. 14.62EPCh. 14 - Prob. 14.63EPCh. 14 - Prob. 14.64EPCh. 14 - Draw the structure of the aldehyde or ketone...Ch. 14 - Draw the structure of the aldehyde or ketone...Ch. 14 - Prob. 14.67EPCh. 14 - Prob. 14.68EPCh. 14 - Prob. 14.69EPCh. 14 - Prob. 14.70EPCh. 14 - Three isomeric pentanols with unbranched carbon...Ch. 14 - Prob. 14.72EPCh. 14 - Prob. 14.73EPCh. 14 - Prob. 14.74EPCh. 14 - Prob. 14.75EPCh. 14 - Prob. 14.76EPCh. 14 - Prob. 14.77EPCh. 14 - Prob. 14.78EPCh. 14 - Prob. 14.79EPCh. 14 - Prob. 14.80EPCh. 14 - Prob. 14.81EPCh. 14 - Prob. 14.82EPCh. 14 - Prob. 14.83EPCh. 14 - Prob. 14.84EPCh. 14 - Prob. 14.85EPCh. 14 - Prob. 14.86EPCh. 14 - Prob. 14.87EPCh. 14 - Prob. 14.88EPCh. 14 - Prob. 14.89EPCh. 14 - Prob. 14.90EPCh. 14 - Prob. 14.91EPCh. 14 - Classify each of the following compounds as an...Ch. 14 - Draw or write the following for the simplest ether...Ch. 14 - Draw or write the following for the simplest ether...Ch. 14 - Prob. 14.95EPCh. 14 - Prob. 14.96EPCh. 14 - Prob. 14.97EPCh. 14 - Prob. 14.98EPCh. 14 - Prob. 14.99EPCh. 14 - Prob. 14.100EPCh. 14 - Prob. 14.101EPCh. 14 - Prob. 14.102EPCh. 14 - Prob. 14.103EPCh. 14 - Prob. 14.104EPCh. 14 - Prob. 14.105EPCh. 14 - Prob. 14.106EPCh. 14 - Prob. 14.107EPCh. 14 - Prob. 14.108EPCh. 14 - Prob. 14.109EPCh. 14 - Prob. 14.110EPCh. 14 - Prob. 14.111EPCh. 14 - Prob. 14.112EPCh. 14 - Prob. 14.113EPCh. 14 - Give common names for all ethers that are...Ch. 14 - How many isomeric ethers exist when the R groups...Ch. 14 - Prob. 14.116EPCh. 14 - Prob. 14.117EPCh. 14 - Draw condensed structural formulas for the...Ch. 14 - Prob. 14.119EPCh. 14 - Prob. 14.120EPCh. 14 - Prob. 14.121EPCh. 14 - Prob. 14.122EPCh. 14 - Prob. 14.123EPCh. 14 - How do the chemical reactivities of ethers compare...Ch. 14 - Explain why ether molecules cannot hydrogen-bond...Ch. 14 - How many hydrogen bonds can form between a single...Ch. 14 - Classify each of the following molecular...Ch. 14 - Classify each of the following molecular...Ch. 14 - Prob. 14.129EPCh. 14 - Prob. 14.130EPCh. 14 - Prob. 14.131EPCh. 14 - Draw a condensed structural formula for each of...Ch. 14 - Prob. 14.133EPCh. 14 - Prob. 14.134EPCh. 14 - Prob. 14.135EPCh. 14 - Prob. 14.136EPCh. 14 - Prob. 14.137EPCh. 14 - For each of the following pairs of compounds,...Ch. 14 - Assign an IUPAC name to each of the following...Ch. 14 - Prob. 14.140EPCh. 14 - Prob. 14.141EPCh. 14 - Prob. 14.142EPCh. 14 - Prob. 14.143EPCh. 14 - Prob. 14.144EPCh. 14 - Prob. 14.145EPCh. 14 - Prob. 14.146EP
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