
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Chapter 14, Problem 14.24P
Interpretation Introduction
Interpretation:
The relation between
Concept introduction:
The voltage of a battery is calculated as
Cell voltage = potential of right hand electrode(
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Identify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.
Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.
Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
Chapter 14 Solutions
Quantitative Chemical Analysis
Ch. 14.1 - Prob. 1TYCh. 14.1 - Prob. 2TYCh. 14.1 - Prob. 3TYCh. 14.1 - Prob. 4TYCh. 14.2 - Prob. 5TYCh. 14.4 - Prob. 6TYCh. 14.4 - Prob. 7TYCh. 14.4 - Prob. 8TYCh. 14.5 - Prob. 9TYCh. 14.5 - Prob. 10TY
Ch. 14.6 - Prob. 11TYCh. 14.7 - Prob. 12TYCh. 14 - Prob. 14.AECh. 14 - Prob. 14.BECh. 14 - Prob. 14.CECh. 14 - Prob. 14.DECh. 14 - Prob. 14.EECh. 14 - Prob. 14.FECh. 14 - Prob. 14.GECh. 14 - Prob. 14.HECh. 14 - Prob. 14.IECh. 14 - Prob. 14.JECh. 14 - Prob. 14.KECh. 14 - Prob. 14.1PCh. 14 - Prob. 14.2PCh. 14 - Prob. 14.3PCh. 14 - Prob. 14.4PCh. 14 - Prob. 14.5PCh. 14 - Prob. 14.6PCh. 14 - Prob. 14.7PCh. 14 - Prob. 14.8PCh. 14 - Prob. 14.9PCh. 14 - Prob. 14.10PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Prob. 14.47PCh. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. 14.52PCh. 14 - Prob. 14.53P
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