Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
Question
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Chapter 1, Problem 1.AE

(a)

Interpretation Introduction

Interpretation:

Molarity of 500 mL methanol solution of 25.00 mL methanol in chloroform has to be calculated.

Concept Introduction:

Molarity is one of the parameters used to express concentration of a solution.  It is expressed as,

Molarity = number of moles of solutevolume of solution in L

(a)

Expert Solution
Check Mark

Answer to Problem 1.AE

Molarity of 500 mL methanol solution made of 25.00 mL methanol in chloroform is calculated as 1.235 M.

Explanation of Solution

Calculate the number of moles of solute methanol to determine.

Given that volume of methanol is 25.00 mL this can be converted to mass as,

density = massvolume

Rewriting the above equation to calculate mass of methanol,

mass=volume×density

Given that density of methanol is 0.7914 g/mL. Therefore,

mass of methanol = 25.00 mL ×0.7914 g/mL = 19.785 g

no.of moles of methanol = massmolar mass = 19.785 g32.04 g/mol =   0.6175 mol

Volume of solution is 500 mL(= 0.5 L)

Now calculate the molarity of methanol in 500 mL solution containing 25.00 mL (=25.00 g) of methanol as shown below,

Molarity  number of moles of methanolvolume of solution in L = 0.6175 mol0.5 L = 1.235 M

Conclusion

Conclusion: 

Given the density of methanol solution, its molarity is calculated using relevant formula.

(b)

Interpretation Introduction

Interpretation:

Molality of 500 mL methanol solution of 25.00 mL methanol in chloroform has to be calculated.

Concept Introduction:

Molality is one of the many parameters that is used to express concentration of a solution.  It is expressed as,

Molality = number of moles of solutemass of solvent in kg

(b)

Expert Solution
Check Mark

Answer to Problem 1.AE

Molality of 500 mL methanol solution made of 25.00 mL methanol in chloroform is calculated as 0.873 m.

Explanation of Solution

Volume of solution is 500 mL.  It is converted to mass –

density = massvolume

Rewriting the above equation to calculate mass of solution,

mass=volume×density

Given that density of solution is 1.454 g/mL. Therefore,

mass of solution = 500 mL ×1.454 g/mL = 727 g

727 g of solution contains 25.00 mL of methanol which is equivalent to 19.785 g methanol as calculated in previous step.  Therefore mass of solvent chloroform is,

727 g of solution  = 19.78 g of methanol + mass of chloroformmass of chloroform      = 727 g - 19.785 g  = 707.215 g = 0.707215 kg

Number of moles of methanol as calculated in previous step is 0.6175 mol.

Molality of methanol is calculated as,

Molality of methanol number of moles of methanolmass of chloroform in kg = 0.6175 mol0.707215 = 0.873 m

Conclusion

Conclusion: 

Given the density of methanol solution, its molality is calculated using relevant formula.

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