Chapter 1.2, Problem 2TY

Interpretation Introduction

Interpretation:

Formula mass of $CaS{O}_4$ has to be calculated.  Molarity of $CaS{O}_4$ in $50mL$ solution containing $1.2g$ of $CaS{O}_4$ has to be calculated.  Amount of $CaS{O}_4$ present in $50mL$ of $0.086M$ $CaS{O}_4$ has to be calculated.

Concept Introduction:

Molarity is one of the parameters used to express concentration of a solution.  It is expressed as,

$\text{Molarity = }\frac{number\text{ of }molesof\text{ solute}}{volume\text{ of solution in L}}$

Formula mass of a compound is equivalent to sum of atomic mass of the elements in the empirical formula of the compound.